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Nesterboy [21]
4 years ago
10

Roland had $10,500 in medical expenses last year and has no medical insurance. The IRS allows medical expense deductions for the

amount that exceeds 7.5% of a taxpayer's adjusted gross income. If Roland's adjusted gross income is $31,000, how much can he claim as a medical deduction?
Mathematics
1 answer:
Sloan [31]4 years ago
8 0
$8,175
you may have to work it out if the numbers are different but this should be the correct answer
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A city has a population of 23,000 in the year 2014, 27,600 in the year 2015, 33,120 in the year 2016, and 39,744 in the year 201
Mkey [24]

Answer:

A. 142,410

Step-by-step explanation:

For this purpose we have to find the pattern in previously given information

The given information is:

23000, 27600, 33120, 39744

The given sequence can be assumed as a geometric sequence

The common ratio is:

r = 27600/23000

r = 1.2

Hence the next term is obtained by multiplying with 1.2

So,

Population in:

2018 = 39744*1.2 = 47692.8

2019 = 47692.8 * 1.2 =57231.36

2020 = 57231.36*1.2 =68677.632

2021 =68677.632 * 1.2 = 82413.1584

2022= 82413.1584 * 1.2 =98895.79

2023= 98895.79 * 1.2 = 118674.948

2024 = 118674.948*1.2 = 142409.9376

Since the number of person/ population should be a whole number so,

The population in 2024 will be 142410

So, Option A is correct ..

4 0
3 years ago
If the length I of a rectangle is 3 more than twice the width w. The area is 90. Find the width
rjkz [21]

Answer:

w = 6

Step-by-step explanation:

Givens

Area = 90

Let the width = w

Let the length = 2w + 3

Formula

Area = L * W

Solution

Area = (2w + 3)*w

Area = (2w + 3)* w = 90                   Remove the brackets.

Area = 2w^2 + 3w = 90                   Subtract 90 from both sides.

2w^2 + 3w - 90 = 0    

This will factor into

(w - 6)(2w + 15) = 0

Only w - 6 will = a zero that makes sense when speaking of an area

w - 6 = 0

w = 6

L = 2*w  + 3

L = 2*6 + 3

L = 15

The width is 6

7 0
4 years ago
A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence
damaskus [11]

Answer:

Following are the solution to this question

Step-by-step explanation:

Please find the complete question in the attached file.

In point a:

a=0.05 \\\\| Z(0.025)|= 1.96  \text{(check in normal table)} \\\\ 95 \% \  CI \\\\\bar x  \pm  \ Z \times \frac{s}{\sqrt{n}}\\\\\to 80 \pm  1.96 \times \frac{15}{\sqrt{60}} \\\\\to (76.20448, 83.79552)

In point b:

95 \%  \ CI \ is \\\\ \bar x  \pm  Z \times \frac{s}{\sqrt{n}}\\\\\to  80 \pm 1.96 \times \frac {15}{\sqrt{120}}\\\\\to (77.31616,  82.68384)

In point c:

A large sample is a smaller error margin.

8 0
3 years ago
Beaker A contains 1 liter which is 15 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which
Tanzania [10]

Answer:

Add 1.25 litres of oil.

Step-by-step explanation:

Contents in beaker A implies;

15% of oil in 1 litre = 0.15 litres of oil

So that, there are 0.15 litres of oil and 0.85 litres of vinegar in beaker A.

Contents in beaker B implies:

55% of oil in 2 litres = 1.1 litres of oil

So that, thee are 1.1 litres of oil and 0.9 litres of vinegar in beaker B.

Half of contents of B poured into A implies that beaker A now contains:

0.15 litres + 0.55 litres = 0.7 litres of oil

0.85 litres + 0.45 litres = 1.3 litres of vinegar

The percentage of oil in A now = \frac{0.7}{2} x 100%

                                                    = 35%

To increase the percentage of oil to 60%, then:

0.7 litres + 1.25 litres = 1.95 litres of oil

But the new total litres of the content in beaker A = 3.25 litres

So that;

\frac{1.95}{3.25} x 100% = 60%

Therefore, to produce a mixture which is 60% oil, add 1.25 litres of oil.

7 0
3 years ago
Hello I was wondering if you can help me list these from least to greatest ​
netineya [11]

Answer:

See  below.

Step-by-step explanation:

Convert to decimal form

7 3/5 = 7.6

7 7/10 = 7.7

10 2/5 = 10.4

8 1/2 = 8.5

So the answer is

7 3/5 , 7 7/10, 8.3, 8.1/2, 10.2  10 2/5, 11.1.

8 0
3 years ago
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