N³- n² + 3n - 3 = (n²+3 )(x-1 )
Answer:
Correct option: A
Step-by-step explanation:
The angle BDC inscribe the arc mBC, so we have that:
mBDC = (1/2) * mBC
mBDC = (1/2) * 118 = 59°
From the secants relation in a circle, we have that:
mA = (1/2) * (mBC - mDE)
35 = (1/2) * (118 - mDE)
70 = 118 - mDE
mDE = 48°
The sum of the arcs is 360°, so we have:
mBC + mCD + mDE + mBE = 360
118 + mCD + 48 + 76 = 360
mCD = 360 - 118 - 48 - 76 = 118°
The angle mCBD inscribes the arc mCD, so we have:
mCBD = (1/2) * mCD = (1/2) * 118 = 59°
The angles mCBD and mBDC are equal, so the triangle is isosceles.
Correct option: A
The solution to the system of equations is (3, 2)
<h3>System of equation</h3>
Give the system of equation below
y = -x + 5
y=x-1
Equate both expression
-x+5 =x - 1
Equate
-x - x = -1 - 5
-2x = -6
x = 3
Since y = x - 1
y = 3 - 1
y = 2
Hence the solution to the system of equations is (3, 2)
Learn more on system of equation here: brainly.com/question/25976025
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Answer:
-8
Step-by-step explanation:
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