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3 years ago

Simplify the equation √5 + √5

Mathematics

1 answer:

Ronch [10]3 years ago

4 0

You can treat sq rt5 as a variable even though it is a number:

Ex: x + x = 2x

Or as a number: 5 + 5 = 10 or 2(5)

So sq rt5 + sq rt5 = 2sq rt5

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Dominic runs a farm stand that sells peaches and grapes. Yesterday Dominic sold 34 pounds of peaches and 45 pounds of grapes for

scoray [572]

Answer:

34x + 45y = 192.25

47x + 16y = 208

Step-by-step explanation:

Let x stand for peaches.

Let y stand for grapes.

Since we know that yesterday he sold 35 pounds of peaches ( x ) and 45 pounds of grapes ( y ) for $192.25, we can create an equation to represent this using two variables; peaches and grapes.

We can do the same thing with the amount of peaches and grapes he sold today. Once we make this equation, we will have two equations to make the system of equations to solve for x and y.

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3 years ago

13. What is the highest number of degrees that an angle can have?<br> 180<br> 360<br> 90<br> 270

kykrilka [37]

Answer:

360

Step-by-step explanation: A full angle is 360. 90*4=360.

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3 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

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3 years ago

Can someone help me factor 4x^2-36x+32? Help!!

S_A_V [24]

4 times (x^2-9x+8). Hope that helps!

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3 years ago

How do you write 9.009 as a percentage?

Oksanka [162]

900.9% would be 9.009 as a percentage.

It's 900% because it's a whole number and it's .9% because of the last 9 in the number (the thousandth - 3 digits after the decimal).

6 0

2 years ago

Simplify the equation √5 + √5​

Simplify the equation √5 + √5