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bixtya [17]
3 years ago
5

PLEASE HELP ASAP!! WILL MARK BRAINLIEST!

Mathematics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

15) 37 16) -5x+13=-112, x=25 23) l=38, w=19

Step-by-step explanation:

15) l=5w+2, 2l+2w=88

2(5w+2)+2w=88

12w+4=88

w=7, l=37

16a) -5x+13=-112

16b) x=25

23) l=2w, 2l+2w=114

2l+l=114

l=38, w=19

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morpeh [17]

Answer:

2nd one is corect

60% is 93.49$ but u are getting 100$ discount so 2nd is ans

4 0
2 years ago
Please anyone can give me it's urgent....​
Pavlova-9 [17]

Step-by-step explanation:

From the figure it is clear that:

x+110°=180

x=180-110

x=70

For y:

the left exterior angle of line q is also70.

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y=70

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3 0
3 years ago
Question 4 please. I will mark brainliest!! i would at least like the equation of the graph thank you
Anestetic [448]

Answer:

a. -3 < x ≤ 5

b. -3 ≤ y < 3

c.  (0, 0)

d. x = -3, x = 1, x = 5

e. -3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. (-1, -1), and (3, -3)

Step-by-step explanation:

a. The domain of a function is the set of the possible independent variable values which is -3 < x ≤ 5

b. The range of a function is the set of the possible values of the dependent variable which is -3 ≤ y < 3

c. The y-intercept is the point the graph crosses the y-axis

The y-intercept in the graph is the point (0, 0)

d. f(x) ≥ 0  when x = -3, x = 1, x = 5

f(x) ≥ 0 over the following range; -3 < x ≤ - 1.5, 0 ≤ x ≤ 1.5, 4.5 ≤ x ≤ 5

e. The intervals over which f(x) is decreasing are;

-3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. The local minimums where f(x) has the minimum values are;

(-1, -1), and (3, -3)

3 0
3 years ago
What is the solution set of the equation 30/x^2-9 +1=5/x-3
gizmo_the_mogwai [7]
\frac{30}{x^{2} - 9 + 1} = \frac{5}{x - 3} \\\frac{30}{x^{2} - 8} = \frac{5}{x - 3} \\5(x^{2} - 8) = 30(x - 3) \\5(x^{2}) - 5(8) = 30(x) - 30(3) \\5x^{2} - 40 = 30x - 90 \\5x^{2} + 50 = 30x \\5x^{2} - 30x + 50 = 0 \\5(x^{2}) - 5(6x) + 5(10) = 0 \\5(x^{2} - 6x + 10) = 0 \\\frac{5(x^{2} - 6x + 10)}{5} = \frac{0}{5} \\x^{2} - 6x + 10 = 0 \\x = \frac{-(-6) \± \sqrt{(-6)^{2} - 4(1)(10)}}{2(1)} \\x = \frac{6 \± \sqrt{36 - 40}}{2} \\x = \frac{6 \± \sqrt{-4}}{2} \\x = \frac{6 \± 2i}{2} \\x = 3 \± i \\x = 3 + i\ or\ x = 3 - i

The answer is D.
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3 years ago
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alina1380 [7]
The answer i got was 28000
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