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lianna [129]
3 years ago
15

Solve x2 – 8x + 15 < 0.

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0
X2 - 8x + 15 = 0
(x  - 3)(x - 5) = 0
critical points are at 3 and 5
strojnjashka [21]3 years ago
4 0
Answer:

<span>x=3,5</span>

Explanation:

<span><span>x2</span>−8x+15=0</span>

Try to express the terms of the equation in square form.

Adding 16 both sides of the equation,

<span><span>(<span>x2</span>−2⋅x⋅4+<span>42</span>)</span>+15=16</span>
<span>or,<span><span>(x−4)</span>2</span>+15−16=0</span>
<span>or,<span><span>(x−4)</span>2</span>−1=0</span>
<span>or,<span><span>(x−4)</span>2</span>−<span>12</span>=0</span>

This is the <span><span>a2</span>−<span>b2</span>=<span>(a+b)</span><span>(a−b)</span></span>form.

<span><span>(x−4+1)</span><span>(x−4−1)</span>=0</span>
<span>or,<span>(x−3)</span><span>(x−5)</span>=0</span>

Now, equate both the terms to zero since both of them when multiplied, give zero.

Either,
<span>x−3=0</span>
<span>∴x=3</span>

Or,
<span>x−5=0</span>
<span>∴x=5</span>

<span>Ans:x=3,<span>5   Hope this helpsXD...!!!
</span></span>

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