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MA_775_DIABLO [31]
3 years ago
7

Im pretty bad with coordinates anyone wanna help with an explanation and and answer please? Ty ​

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
4 0

Answer:

About 9.4

Step-by-step explanation:

64+25=89

sqr root of 89 is 9.4339

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What is the slope of the line that passes through 2,-3 and -2,10​
mafiozo [28]

Answer:

-13/4

Step-by-step explanation:

10-(-3)=13

-2-2=-4

13/-4

4 0
3 years ago
Help find missing segment??
AleksandrR [38]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Let x as the missing segment.

_________________________________

According to the Thales theorem :

\frac{26}{x}  =  \frac{12}{36}  \\

\frac{26}{x}  =  \frac{12}{12 \times 3}  \\

\frac{26}{x}  =  \frac{1}{3}  \\

Inverse both sides

\frac{x}{26}  =  \frac{3}{1}  \\

\frac{x}{26}  = 3 \\

Multiply sides by 26

26 \times  \frac{x}{26}  = 26 \times 3 \\

x = 26 \times 3

x = 78

Thus the missing segment has a measure of 78 .

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7 0
3 years ago
On a particular day, the wind added 4 miles per hour to Jaime's rate when she was rowing with the wind and subtracted 4 miles pe
larisa [96]
Nice so
remember
t=d/s
a(b+c)=ab+ac

time=distance/speed

lets say s=jamie's normal speed
speed agains wind=s-4
speed with wind=s+4

30 miles is agains wind
distance is 54 with wind


t=d/s
t=30/(s-4)
t=54/(s+4)

since they are both equal to t, set them equal to each other

30/(s-4)=54/(s+4)
multipliy both sides by (s+4)(s-4)
30(s+4)=54(s-4)
distribute
30s+120=54s-216
subtract 30s from both sides
120=24s-216
add 216 to both sides
336=24s
divide both sides by 24
14=s


answer is 14 miles per hour without wind
8 0
3 years ago
Paige has 4 more balloons than Zoee. Emma  has 2 more balloons than Paige. Altogether they have 100 balloons. How many does each
aksik [14]
52 and 48 if you take away 2 from 50 then,add it to the other 50 52+48
6 0
3 years ago
usa el teorema de la altura para proponer como se podria construir un segmento cuya longitud sea media proporcional entre dos se
Mrac [35]
Usando el teorema de altura 

El teorema de altura relaciona la altura (h) de un triángulo rectángulo (ver figura) y los catetos de dos triángulos que son semejantes al anterior ABC, al trazar la altura (h) sobre la hipotenusa. De manera que e<span>n todo </span>triángulo rectángulo, la altura (h<span>) relativa a la </span>hipotenusa<span> es la </span>media geométrica<span> de las dos proyecciones de los </span>catetos<span> sobre la </span>hipotenusa<span> (</span>n<span> y </span>m<span>). Es decir, se cumple que:

</span>\frac{n}{h}= \frac{h}{m}

Dado que el problema establece <span>construir un segmento cuya longitud sea media proporcional entre dos segmentos de 4 y 9 cm, entonces, digamos que n = 4cm y m = 9cm tenmos que:

</span>\frac{4}{h}= \frac{h}{9}

De donde:

h= \sqrt{(4)(9)}=\sqrt{36}=6cm

¿Cómo se podria construir si los segmentos son de a cm y b cm?

Si los segmentos son de a y b cm entonces a y b son parámetros que pueden tomar cualquier valor positivo siempre que se cumpla que:

h= \sqrt{ab}

6 0
3 years ago
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