Answer:
C. It is a male with atleast one dominant allele
Explanation:
In the given pedigree, the two normal parents of the generation I have one daughter with the attached earlobe. Since the trait is recessive, the daughter should be homozygous recessive to express the trait. The genotype of the daughter (shaded circle in generation II) is "aa". To have a daughter with "aa" genotype, both the parents should have one copy of "a" allele. So, the genotype of both parents is "Aa".
In generation II, individual A is non-shaded square. Squares represent males in a pedigree. Since its not shaded, it does not have attached earlobe. Both the parents are heterozygous dominant for attached earlobes (Aa x Aa = 1/4 AA : 1/2 Aa : 1/4 aa). The genotype of this individual may be AA or Aa.
Answer:
Chitinous exoskeleton and segmented bodies.
Explanation:
Phylum Arthropoda are known as jointed legs species which include crabs, spiders, ants, etc. The important characteristic of Arthropoda is they have a hard chitinous exoskeleton that provides them protection and gives flexibility. These phylum species can survive in both terrestrial and marine habitats. Some characteristics of phylum Arthropoda are given below:
1) They have Chitinous exoskeleton which is hardened.
2) Their digestive tract is present at opposite ends of the body and complete with the mouth and anus.
3) They contain jointed limbs.
4) The body structure of these species is showing bilateral symmetry.
Answer:
cos it works on humans better i guess
Explanation:
The genes for sex-linked disorders are found on a sex chromosome, but the genes for other inherited genetic disorders are found on other chromosomes.
