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insens350 [35]
3 years ago
5

In the family tree below, people with the recessive trait of attached earlobes

Biology
1 answer:
madam [21]3 years ago
5 0

Answer:

C. It is a male with atleast one dominant allele

Explanation:

In the given pedigree, the two normal parents of the generation I have one daughter with the attached earlobe. Since the trait is recessive, the daughter should be homozygous recessive to express the trait. The genotype of the daughter (shaded circle in generation II) is "aa". To have a daughter with "aa" genotype, both the parents should have one copy of "a" allele. So, the genotype of both parents is "Aa".

In generation II, individual A is non-shaded square. Squares represent males in a pedigree. Since its not shaded, it does not have attached earlobe. Both the parents are heterozygous dominant for attached earlobes (Aa x Aa = 1/4 AA : 1/2 Aa : 1/4 aa). The genotype of this individual may be AA or Aa.

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Answer:

The correct answer would be -

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A mature male or female haploid germ cell that fuses with another gamete of the opposite sex during the process of fertilization to make a zygote in sexual reproduction.

The law of Independent Assortment presented by Mendel says that alleles for different traits are passed and assort independently of one another in the gametes.

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2) If Y and R on the same chromosomes and no crossing over occurs then they will produce only two gametes as Y and R will not come together - Yr & yR.

3).  if dominant Y and recessive r are on the same chromosome, no crossing over then only two gametes will form as Y and r will not assort together - YR & yr.

4). if dominant Y and R are on the same chromosome, 50% crossing over produces 4 types of gametes, YR, Yr, yR & yr.

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