First let's talk about the blue line.
You can see its rising so its slope is certainly positive. But by how much is it rising? You can observe that each unit it rises it goes 1 forward and 1 up so its slope is the ratio of 1 up and 1 forward which is just 1.
We have thusly,
Now look at where blue line intercepts y-axis, -1. That is our n.
So the blue line has the equation of,
Next the black lines. The black lines are axes so their equations are a bit different.
First let's deal with x-axis, does it have slope? Yes but it is 0. The x-axis is still, not rising nor falling. Where does x-axis intercept y-axis? At 0. So the equation would be,
Now we have y-axis. Does y axis have a slope? Yes but it is 
. The y-axis rises infinitely in no run. Where does it intercept y-axis? Everywhere! So what should the equation be? What if we ask where does y-axis intercept x-axis and write its equation in terms of x. Y-axis intercepts x-axis at 0 which means its equation is,
That is, every point of a form 
lies on y-axis.
Hope this helps :)
Y+3=2(x-5)
y+3=2x-10
y+3+10=2x
y+13=2x
2x-y=13
Answer:
A. b2 – 4ac = 0
Step-by-step explanation:
Hey user☺☺
Option a is correct
Because the graph has only one solution.
As the graph touches the x-axis at one point that means that it will have only one solution for x. But we know that a quadratic equation has two solutions. So the graph will have two equal solution and therefore the discriminant will be 0.
Hope this will help☺☺
so I think the answer is very difficult ask to someone else
Step-by-step explanation:
xy=4
2x-y+2=0
