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scoray [572]
3 years ago
13

Two mechanics worked on a car. The first mechanic worked for

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0
X - the rate charged by the first mechanic
y - the rate charged by the second mechanic

The sum of the two rates was $155.
x+y=155 \\
y=155-x

The first mechanic worked for 10 hours, the second mechanic worked for 5 hours, and together they charged $1000.
10x+5y=1000 \ \ |\div 5 \\
2x+y=200 \\
y=200-2x

Set 155-x and 200-2x equal to each other:
155-x=200-2x \\
-x+2x=200-155 \\
x=45 \\ \\
y=155-x=155-45=110

The rate charged by the first mechanic was $45, and the rate charged by the second mechanic was $110.
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Which toy pack cost of 2.50 per toy ?(brainlist will be given out)!!
Artemon [7]

Answer: Yo-yo

Concept:

In order to find the Cost Per Toy, we need to do the operation Cost / Toy.

Solve:

Slinky = Cost / Toy = 9 / 5 = $1.8 per toy

Wind-up robot = Cost / Toy = 16 / 8 = $2 per toy

<u>Yo-yo = Cost / Toy = 15 / 6 = $2.5 per toy</u>

Emoji beach ball = Cost / Toy = 3 / 2 = $1.5 per toy

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
Easy question!<br><br> 2x - 3 = 8<br><br> solve plz
statuscvo [17]
2x - 3 = 8
add 3 to both sides
2x = 11
divide both sides by 2
x = 5.5
7 0
3 years ago
Solve for u, z, y, and t:
nikitadnepr [17]

A.\\\\\dfrac{y}{a}-b=\dfrac{y}{b}-a\qquad\text{multiply both sides by }\ ab\neq0\\\\by-ab^2=ay-a^2b\qquad\text{add}\ ab^2\ \text{to both sides}\\\\by=ay+ab^2-a^2b\qquad\text{subtract}\ ay\ \text{from both sides}\\\\by-ay=ab^2-a^2b\qquad\text{distributive}\\\\(b-a)y=ab^2-a^2b\qquad\text{divide both sides by}\ (b-a)\\\\\boxed{y=\dfrac{ab^2-a^2b}{b-a}}\to y=\dfrac{ab(b-a)}{b-a}\to\boxed{y=ab}


B.\\t+\dfrac{b^2}{a}=\dfrac{bt}{a}+a\qquad\text{multiply both sides by}\ a\neq0\\\\at+b^2=bt+a^2\qquad\text{subtract}\ b^2\ \text{from both sides}\\\\at=bt+a^2-b^2\qquad\text{subtract}\ bt\ \text{from both sides}\\\\at-bt=a^2-b^2\qquad\text{distributive}\\\\(a-b)t=a^2-b^2\qquad\text{divide both sides by}\ (a-b)\neq0\\\\\boxed{t=\dfrac{a^2-b^2}{a-b}}\to t=\dfrac{(a-b)(a+b)}{a-b}\to\boxed{t=a+b}

8 0
3 years ago
On a test, wrong answers are worth -5.25 points and right answers are worth 3.5 points. So far, Marshall has one right answer an
Over [174]

Answer:

Marshall's current score is - 1.75 points

Step-by-step explanation:

From the question,

Wrong answers are worth -5.25 points and right answers are worth 3.5 points.

Currently, Marshall has one right answer and one wrong answer.

To determine Marshall's current score, we will multiply the number of right answers has by 3.5 points and multiply the number of wrong answers by -3.5 points and then add the results.

Number of right answers = 1

Number of wrong answers = 1

For the right answer, he has

1 × 3.5 points = 3.5 points

For the wrong answer, he has

1 × - 5.25 points = -5.25 points

Hence, Marshall's current score is

3.5 points + ( -5.25 points) = 3.5 points - 5.25 points

= - 1.75 points.

Hence, Marshall's current score is - 1.75 points.

8 0
3 years ago
Is 25 possible solution to the following inequality?<br><br> 100 &lt; 4x
ddd [48]

Answer:

No

Step-by-step explanation:

100 < 4x

Divide each side by 4

100/4 < 4x/4

25 < x

It states is must be less than

But 25 is equal to 25, so it cannot be a solution

7 0
3 years ago
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