Question

Find sin60 A.1/2 B.2/2 C.3/2

Answer 1

Answer: $\frac{\sqrt{3} }{2}$

Step-by-step explanation:

To find sin(60), you need to know the unit circle. Sin(60) is the same as sin(π/3). On the unit circle, sin(π/3) is √3/2. We know this because the coordinates are (cos, sin). Sin is the y coordinate.

Answer 2

Answer:

$\huge\boxed{\sin60^o=\dfrac{\sqrt3}{2}}$

Step-by-step explanation:

Let's take a right triangle with acute angles 30° and 60°.

We know that the ratio of the sides of such a triangle is 2 : 1 : √3

(look at the picture)

We know:

$sine=\dfrac{opposite}{hypotenuse}$

In this triangle we have:

$opposite=a\sqrt3\\hypotenuse=2a$

Substitute:

$\sin60^o=\dfrac{a\sqrt3}{2a}$         cancel a

$\sin60^o=\dfrac{\sqrt3}{2}$