Answer: C) ASA = ASA
Refer to the diagram below. I've used color coding to match up the given statements with the drawing. Note how the red segments are between the blue and green angles. So we use ASA to prove the triangles are congruent.
Answer:
(3)3 - 21/3 + 6 --> 9 - 27/3 --> -18/3
Answer with Step-by-step explanation:
We know that
Number of zeroes of a quadratic function are 2.
When discriminant D
D=0
Roots are equal and real
D>0
Roots are real and different
D<0
Roots are not exist.
a.D=0
Number of zeroes=2
Zeroes are equal and real.
b.D=-36
Zeroes of quadratic function does not exist.
c.D=3
Number of zeroes=2
zeroes are real and different
d.D=2
Number of zeroes=2
zeroes are real and different
e.D=100
Number of zeroes=2
zeroes are real and different
D=-4
Zeroes of quadratic function does not exist.
Answer:
![y=-4x+17](https://tex.z-dn.net/?f=y%3D-4x%2B17)
Step-by-step explanation:
![\begin{pmatrix}4&1\end{pmatrix}\quad \mathrm{and}\quad \begin{pmatrix}2&9\end{pmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bpmatrix%7D4%261%5Cend%7Bpmatrix%7D%5Cquad%20%5Cmathrm%7Band%7D%5Cquad%20%5Cbegin%7Bpmatrix%7D2%269%5Cend%7Bpmatrix%7D)
![\mathrm{Computing\:dot\:product\:of\:two\:vectors}:\quad \left(x_1,\:\:\ldots ,\:\:x_n\right)\cdot \left(y,\:\:\ldots ,\:\:y_n\right)=\sum _{i=1}^nx_iy_i](https://tex.z-dn.net/?f=%5Cmathrm%7BComputing%5C%3Adot%5C%3Aproduct%5C%3Aof%5C%3Atwo%5C%3Avectors%7D%3A%5Cquad%20%5Cleft%28x_1%2C%5C%3A%5C%3A%5Cldots%20%2C%5C%3A%5C%3Ax_n%5Cright%29%5Ccdot%20%5Cleft%28y%2C%5C%3A%5C%3A%5Cldots%20%2C%5C%3A%5C%3Ay_n%5Cright%29%3D%5Csum%20_%7Bi%3D1%7D%5Enx_iy_i)
![=4\cdot \:2+1\cdot \:9](https://tex.z-dn.net/?f=%3D4%5Ccdot%20%5C%3A2%2B1%5Ccdot%20%5C%3A9)
![=17](https://tex.z-dn.net/?f=%3D17)
Answer:
B) 34°
Step-by-step explanation: