Answer:
c. f(x)=x(x+2)(x-1)(x-4)
Step-by-step explanation:
Where it says "as x goes to negative infinity" then "y goes to infinity" (that's the part with the infinity symbols) that means the graph is going up at it's left end. This curve is a quartic (4th degree) which means its left and right ends are kind of parabola-ish, but the middle is not the neat u-ish, v-ish shape of a parabola; it's more like a wonky, noodle-ish wavy affair. Anyway, LIKE a parabola when the beginning of the equation is positive, the two ends point up. That's what's happening here and so we can eliminate b. and d. as potential answers.
Since -2, 0, 1, 4 are zeros (which are solutions...and also x-intercepts) we can find the factors of the function.
If x = -2
ADD 2 to both sides.
x + 2 = 0
This means (x+2) is a factor.
This is enough info to select answer c. but let's verify the other factors.
If x = 1
SUBTRACT 1 from both sides.
x - 1 = 0
Thus means (x - 1) is a factor.
If x = 4
SUBTRACT 4 from both sides.
x - 4 = 0
(x - 4) is a factor.
You can see c. has all these factors as well as x, because x=0 already, so x is a factor too.
I think of this as a working backwards problem, bc usually you have to factor and solve. This one, you have solutions (which are zeros and x-intercepts) and work backwards to find factors and multiply them together to find the function.
Answer:
x = 2 ± √11 (I believe)
Step-by-step explanation:
Step-by-step explanation:
"Solutions to the equation" just means that they are points on the line. To find out if these two points land on this line, plug each one in, like this:
1.5 = (1/4)(1) + (5/4)
1.5 = (1/4) + (5/4)
1.5 = (6/4)
1.5 = 1.5
Since the expression is true, this point is on the line.
Do the same process for the second point (remember a point is formatted (x,y)) and see if it is also a point on the line.
To find the x-intercept, simply plug in 0 for y and see what you get. It should look like (x,0).
