I think the answer is 25,200 J (or 25.2 kJ)
Could you put me as brainliest?
I have included the work in the attached file. The correct answer is C. 28.2 grams of Carbon
Answer:
222.3 ml of a 0.130 M aqueous solution of chromium (II) nitrate must be taken to obtain 5.08 grams of the salt.
Explanation:
Being:
- Cr: 52 g/mole
- N: 14 g/mole
- O: 16 g/mole
the molar mass of chromium (II) nitrate, Cr(NO₃)₂ is:
Cr(NO₃)₂ = 52 g/mole + 2* (14 g/mole + 3* 16 g/mole)= 176 g/mole
So: if 176 grams are present in 1 mole of the compound, 5.08 grams in how many moles of the compound will be present?
amount of moles=0.0289 moles
Molarity (M) is the number of moles of solute that are dissolved in a given volume. It is then calculated by dividing the moles of the solute by the volume of the solution:
Molarity is expressed in
So in this case:
- molarity= 0.130 M
- number of moles of solute= 0.0289 moles
- volume= ?
Replacing:
Solving:
volume=0.2223 liters
Being 1 L= 1,000 mL:
volume=0.222 liters= 222.3 mL
<u><em>
222.3 ml of a 0.130 M aqueous solution of chromium (II) nitrate must be taken to obtain 5.08 grams of the salt.</em></u>
Answer:
And=B
Explanation:
The subscripts does represent the relative mass of each type of atom in the compound, it represents relative number of atoms
Answer:
During chemical reactions are broken and to form new substances with different properties, but mass is still .