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3 years ago

How many grams of P3O9 contain 9.67x10^23 atoms of oxygen?

Chemistry

1 answer:

Kobotan [32]3 years ago

6 0

Answer:

49.1 g

Explanation:

First we convert 9.67x10²³ atoms of oxygen into moles, using Avogadro's number:

9.67x10²³ atoms ÷ 6.023x10²³ atoms/mol = 1.60 mol O

Then we calculate how many P₃O₉ moles there would be with 1.60 O moles:

1.60 mol O * $\frac{1molP_3O_9}{9molO}$ = 0.18 mol P₃O₉

Finally we convert 0.18 P₃O₉ moles into grams, using its molar mass:

0.18 mol P₃O₉ * 237 g/mol = 49.1 g

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A student reacts 5.0 g of sodium with 10.0 g of chlorine and collect 5.24 g of sodium chloride. What is the percent yield of thi

Ede4ka [16]

Answer: The percent yield of this combination reaction is 41.3 %

Explanation : Given,

Mass of $Na$ = 5.0 g

Mass of $Cl_2$ = 10.0 g

Molar mass of $Na$ = 23 g/mol

Molar mass of $Cl_2$ = 71 g/mol

First we have to calculate the moles of $Na$ and $Cl_2$ .

$\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}$

$\text{Moles of }Na=\frac{5.0g}{23g/mol}=0.217mol$

and,

$\text{Moles of }Cl_2=\frac{\text{Given mass }Cl_2}{\text{Molar mass }Cl_2}$

$\text{Moles of }Cl_2=\frac{10.0g}{71g/mol}=0.141mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation will be:

$2Na+Cl_2\rightarrow 2NaCl$

From the balanced reaction we conclude that

As, 2 mole of $Na$ react with 1 mole of $Cl_2$

So, 0.217 moles of $Na$ react with $\frac{0.217}{2}=0.108$ moles of $Cl_2$

From this we conclude that, $Cl_2$ is an excess reagent because the given moles are greater than the required moles and $Na$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaCl$

From the reaction, we conclude that

As, 2 mole of $Na$ react to give 2 mole of $NaCl$

So, 0.217 mole of $HCl$ react to give 0.217 mole of $NaCl$

Now we have to calculate the mass of $NaCl$

$\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl$

Molar mass of $NaCl$ = 58.5 g/mole

$\text{ Mass of }NaCl=(0.217moles)\times (58.5g/mole)=12.7g$

Now we have to calculate the percent yield of this reaction.

Percent yield = $\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Actual yield = 5.24 g

Theoretical yield = 12.7 g

Percent yield = $\frac{5.24g}{12.7g}\times 100$

Percent yield = 41.3 %

Therefore, the percent yield of this combination reaction is 41.3 %

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3 years ago

How many hydrogen atoms are in a cycloalkane with 8 carbon atoms?

frosja888 [35]

Cycloalkanes are those saturated organic compounds which exist in the form of Rings. Their Hydrogen Deficiency Index in one. The General formula for cycloalkanes is,
CnH2n
When number of Carbons = 8
Then
C₈H₂₍₈₎

C₈H₁₆

Result:
Cycloalkane containing 8 carbon atoms has 16 hydrogen atoms.

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3 years ago

A student attempts to separate 4.656 g of a sand/salt mixture just like you did in this lab. After carrying out the experiment,

nikitadnepr [17]

Answer:

Explanation:

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Total of sand and salt recovered = 2.775 g + .852 g = 3.627 g .

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percent recovery = (3.627 / 4.656 ) x 100

= 77.9 % .

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2 years ago

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noname [10]

Answer:

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Explanation:

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3 years ago

How many grams of P3O9 contain 9.67x10^23 atoms of oxygen?​

How many grams of P3O9 contain 9.67x10^23 atoms of oxygen?