How many grams of P3O9 contain 9.67x10^23 atoms of oxygen?
1 answer:
Answer:
49.1 g
Explanation:
First we <u>convert 9.67x10²³ atoms of oxygen into moles</u>, using <em>Avogadro's number</em>:
- 9.67x10²³ atoms ÷ 6.023x10²³ atoms/mol = 1.60 mol O
Then we <u>calculate how many P₃O₉ moles there would be with 1.60 O moles</u>:
- 1.60 mol O * = 0.18 mol P₃O₉
Finally we convert 0.18 P₃O₉ moles into grams, using its molar mass:
- 0.18 mol P₃O₉ * 237 g/mol = 49.1 g
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<span>n = c x v
= 1 x 0.025
= 0.025 moles
= n
NaOH = n/v
= 0.025/0.045
= 0.56M
So is it A
0.56 M NaOH</span>