Question

How many grams of P3O9 contain 9.67x10^23 atoms of oxygen?​

Answer 1

Answer:

49.1 g

Explanation:

First we convert 9.67x10²³ atoms of oxygen into moles, using Avogadro's number:

• 9.67x10²³ atoms ÷ 6.023x10²³ atoms/mol = 1.60 mol O

Then we calculate how many P₃O₉ moles there would be with 1.60 O moles:

• 1.60 mol O * $\frac{1molP_3O_9}{9molO}$ = 0.18 mol P₃O₉

Finally we convert 0.18 P₃O₉ moles into grams, using its molar mass:

• 0.18 mol P₃O₉ * 237 g/mol = 49.1 g