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Nonamiya [84]
3 years ago
7

Use the drop-down menus to match the type of intermolecular force to its name.

Chemistry
2 answers:
Ne4ueva [31]3 years ago
4 0

Answer:

Dipole-dipole interactions-  occur between polar molecules

Dipole-induced dipole interactions- occur between polar and nonpolar molecules

London dispersion forces- occur in all substances, but are the most important in nonpolar substances

Hydrogen bond- electrostatic attraction between a hydrogen atom and a highly electronegative atom

van der Waals forces- electrostatic interactions between partially charged regions of a molecule

edg 2020!

geniusboy [140]3 years ago
3 0

Answer:

Dipole-dipole interactions : occur between polar molecules

Dipole-induced dipole interactions: occur between polar and nonpolar molecules

London dispersion forces: occur in all substances, but are the most important in nonpolar substances

Hydrogen bond: electrostactic attraction between a hydrogen atom and a highly electronegative atom

van der Waals forces: electrostatic interactions between partially charged regions of a molecule

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Is the electrolysis of water an oxidation-reduction reaction??
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Answer:

Yes

Explanation:

Electrolysis is an example of redox reaction because reduction takes place at cathode and oxidation takes place at anode and both of these reactions take place simultaneously.

8 0
3 years ago
What is the difference between pure and applied chemistry?
bekas [8.4K]

Answer:

Explanation:

The major difference between pure and applied chemistry is the purpose and intent of the study.

Pure chemistry deals with the study of matter, matter transformations, and interactions between the different materials of the world, for only the sake of gaining empirical knowledge about the various substances that exist in the world. It does not really seek to apply this knowledge to do anything industrial.

Applied chemistry is the study of chemistry with the aim of utilizing this knowledge to solve the various problems that man faces. This approach of study is not for knowledge sake alone, rather it is for industrial application

3 0
3 years ago
Which unit conversion allows you to convert 21.0 gallons into milliliters?
Ulleksa [173]

Answer:

Explanation:

we are given

there are in 0.073 gallons

we can see that there are two non-zero places after decimals

so, there are two siginificant figures

step-1: Change gallons to quarts

we know that

1 gallon = 4 quarts

so, we can write as

step-2: Change into liter

we know that

1 liter = 1.057 quarts

or

step-3: Change into millilitre

we know that

Since, it is asking for only two significant figures

so, we can also write as

...................Answer

3 0
3 years ago
What two elements fill their last electron in the 5s sublevel?
postnew [5]

Answer:Rubidium and Strontium

Explanation:

7 0
3 years ago
A 34.0 g piece of metal is heated to 92.0°C then placed in a beaker of water containing 22.0 g of water at 19.0°C. The temperatu
lapo4ka [179]

Answer:

0.1988 J/g°C

Explanation:

-Qmetal = Qwater

Q = mc∆T

Where;

Q = amount of heat

m = mass of substance

c = specific heat of substance

∆T = change in temperature

Hence;

-{mc∆T} of metal = {mc∆T} of water

From the information provided in this question, For water; m= 22.0g, ∆T = (24°C-19°C), c = 4.18J/g°C.

For metal; m= 34.0g, ∆T = (24°C-92°C), c = ?

Note that, the final temperature of water and the metal = 24°C

-{34 × c × (24°C-92°C)} = 22 × 4.18 × (24°C-19°C)

-{34 × c × (-68°C)} = 459.8

-{34 × c × -68} = 459.8

-{-2312c} = 459.8

+2312c = 459.8

c = 459.8/2312

c = 0.1988

The specific heat capacity of the metal is 0.1988 J/g°C

6 0
3 years ago
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