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julsineya [31]
3 years ago
9

Answer:

Chemistry
2 answers:
scoray [572]3 years ago
6 0

Answer:

b. 2 g/mL

Explanation:

Density=mass/volume.

so: D=10g/5mL

Density=2g/mL

Leni [432]3 years ago
4 0

Answer:

The correct answer is option b.

Explanation:

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Mass of an object = 10 g

Volume of an object  = 5 mL

Density of an object = d

Putting values in above equation, we get:

d=\frac{10 g}{5 mL}=2 g/mL

2 g/mL is the density of an object that has a mass of 10 g and a volume of 5 mL.

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A disturbance in matter that carries energy from one place to another is called
siniylev [52]
The answer you're looking for is: a wave.
6 0
3 years ago
How many moles are in 15 grams of Cr2(CO3)3 ?
Rainbow [258]

Answer:

0.052813386714757

Explanation:

That's what I got, not quite sure if it's right tho

7 0
3 years ago
Bromine has two isotopes 79Br and 81Br, whose masses (78.9183 and 80.9163 amu) and abundances (50.69% and 49.31%, respectively)
Reika [66]

Answer:

Average atomic mass = 79.9034 amu

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

<u>For first isotope: </u>

% = 50.69 %

Mass = 78.9183 amu

<u>For second isotope: </u>

% = 49.31 %

Mass = 80.9163 amu

Thus,  

Average\ atomic\ mass=\frac{50.69}{100}\times {78.9183}+\frac{49.31}{100}\times {80.9163}\ amu

Average\ atomic\ mass=40.0036+39.8998\ amu

<u>Average atomic mass = 79.9034 amu</u>

4 0
3 years ago
Zn + 2 HCl ZnCl2 + H2
son4ous [18]

Answer:

0.153 moles of hydrogen.

B) Multiply 10 grams of Zn x (1 mol Zn/65.39 g)

Explanation:

Given data:

Mass of zinc = 10 g

Moles of hydrogen = ?

Solution:

Chemical equation:

Zn + 2HCl  →  ZnCl₂ +  H₂

Number of moles of zinc:

Number of moles of zinc = mass/ molar mass

Number of moles of zinc = 10 g/ 65.4 g/mol

Number of moles of zinc = 0.153 mol

Now we will multiply the moles of Zn with hydrogen:

                     Zn            :            H₂

                      1              :              1

                     0.153       :            0.153

4 0
3 years ago
If 10.5 g copper chloride react with 12.4 g aluminum what is the limiting reactant
Brut [27]
Molar mass of copper chloride is 134.45 g/mole, so the mole of 10.5 g copper chloride is 10.5/134.45 = 0.078 mole.  Molar mass of aluminum is 27 g/mole, so the mole of 12.4 g aluminium is 12.4/27 = 0.46 mole.  The formula of this reaction is as follows, 2Al + 3CuCl2 ⇒ 2AlCl3 + 3Cu. Thus the molar ratio of the reactants is Al:CuCl2 = 2:3. So to react with 0.078 mole of copper chloride, will need 0.078 x 2/3 = 0.052 moles of aluminum which is less than the given amount (0.46mole).  Therefore, copper chloride is the limiting reactant.
8 0
3 years ago
Read 2 more answers
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