Answer:
![[N_2]=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3D0.0866M)
Explanation:
Hello there!
In this case, in agreement to the chemical reaction, it is possible for us to figure out the equilibrium concentration of the N2 product, via an ICE table plugged in the equilibrium expression:
![Kc=\frac{[N_2][O_2]}{[NO]^2}\\\\2.4x10^3=\frac{x*x}{(0.175-2x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BN_2%5D%5BO_2%5D%7D%7B%5BNO%5D%5E2%7D%5C%5C%5C%5C2.4x10%5E3%3D%5Cfrac%7Bx%2Ax%7D%7B%280.175-2x%29%5E2%7D)
In such a way, when solving for x via quadratic equation or just a solver, it is possible to obtain:
In such a way, since the root 0.0884 M produce a negative concentration of NO (0.175-2*0.0884=-0.0018M), we infer that the correct root is 0.0866 M; therefore, the concentration of N2 at equilibrium is equal to x:
![[N_2]=x=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3Dx%3D0.0866M)
Best regards!
Answer:
C. by its chemical Symbol
Hope this helps!
Based on observation of polar and non-polar molecules, polar molecules would attract each other more strongly.
<h3>What are polar and non-polar molecules?</h3>
Polar molecules are those molecules that can ionize or dissociate into their respective positive and negative ions when in an aqueous solution.
Nonpolar molecules, on the other hand, are not ionic i.e. not dissociating into ions when dissolved in water.
Polar molecules like water (H2O) contains an uneven distribution of cations (+) and anions (-), hence, would be more attracted to one another than nonpolar molecules that have an even distribution of ions.
Learn more about polarity at: brainly.com/question/16106487
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