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hoa [83]
2 years ago
14

Acceleration always refers to a(n)

Chemistry
2 answers:
Harman [31]2 years ago
8 0
B, increase in speed
konstantin123 [22]2 years ago
6 0

Answer:

increase in speed

Step-by-step explanaton:

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A gas occupies 900.0 mL at a temperature of 300K. What is the volume at 132.0 °C?
lozanna [386]
V1/T1=V2/T2
V2=(V1)(T2)/T1
Plug in values given (for the temp you can either turn 300K to 27°C or turn 132°C into kelvin
V2= 4400 mL= 4.4L
8 0
2 years ago
Water enters a 4.00-m3 tank at a rate of 6.33 kg/s and is withdrawn at a rate of 3.25 kg/s. The tank is initially half full.
olga55 [171]

Answer:

At the start of the process, the volume not occupied by the water is 2 m3

Explanation:

At the start of the process you have a half full tank. It means that also a half is empty (not occupied by water).

Since the volume is 4 m3, 2 m3 are full (occupied by water) and 2 m3 (not occupied by water).

The volume in time will be

V(t)=V_0+(f_i-f_o)*t\\\\V(t) = 2 +(6.33/1000-3.25/1000)*t=2+0.00308*t \, \, [m3]

8 0
3 years ago
Which most likely would be a new social issue resulting from the installation of a dam?
irinina [24]
C. Greater exposure to radiation

3 0
3 years ago
Read 2 more answers
HELP PLEASE I WILL GIVE YOU BRAINLIEST
Ksivusya [100]
The first and Third graph
6 0
3 years ago
2.0 kg of carbon is heated from 25°C to 55°C, and absorbs 42600 joules of heat in the process.
Marrrta [24]

Answer: c = 710 J/kg°C or 0.71 J/g°C

Explanation: Heat is expressed in the formula Q = mc∆T. Derive to find the specific heat c. So the formula will become c = Q / m∆T

c = Q / m∆T

= 42600 J / 2 kg ( 55°C - 25°C )

= 710 J /kg°C

Or can be expressed by converting kg to g.

c = 0.71 J /g°C

6 0
3 years ago
Read 2 more answers
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