Question

10-(3x-1)/2=(6x+3)/11 If someone could help that would be great thank you!

Answer 1

If it is :

$10 - \frac{ (3x - 1)}{2} = \frac{(6x + 3)}{11}$

Multiply both sides by 22

$(22 \times 10) - 11 \times (3x - 1) = 2 \times (6x + 3)$

$220 - 33x + 11 = 12x + 6$

$- 33x + 231 = 12x + 6$

Plus both sides 33x

$231 = 33x + 12x + 6$

$231 = 45x + 6$

Subtract sides minus 6

$231 - 6 = 45x$

$45x = 225$

Divided sides by 45

$x = \frac{225}{45}$

$x = 5$

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If it is :

$\frac{10 - (3x - 1)}{2} = \frac{6x + 3}{11}$

Multiply sides by 22

$(11 \times 10) - 11 \times (3x - 1) = 2 \times (6x + 3)$

$110 - 33x + 11 = 12x + 6$

$- 33x + 121 = 12x + 6$

Plus sides 33x

$121 = 12x + 33x + 6$

$121 = 45x + 6$

Subtract sides minus 6

$121 - 6 = 45x$

$45x = 115$

$x = \frac{115}{45}$

$x = \frac{23}{9}$

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And we're done.

Thanks for watching buddy good luck.

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