Answer: B) one
This one point is point U since it is on line segment CD. In contrast, a point like point E is not on line CD, so E is not collinear with C and D.
Answer:
45%
Step-by-step explanation:
Simply divide your partial amount (18 in this case) by your total (40), and you then multiply your answer from 18/40= .45 by 100, and you get 45. This is 45%
Answer:
he answer is 2800, hope this helps!
Step-by-step explanation: :))
Answer:
slope = -3/14
Step-by-step explanation:
y1 - y2 / x1 - x2
They gave you one value, two total coordinates
5-5 = 1
-3 - 11
-14
1/-14
y=1/-14 + b
11= 1/-14(-3) + b
11 = -3/14 + b
17 + 14
b = 15 3/14
A gray kangaroo jumped and it's path through the air is given by
y =
where x is the kangaroo's horizontal distance traveled (in feet) wand y is the corresponding height (in feet).
For maximum distance we have to differentiate this expression.

For maxima or minima
=0
-0.0267×2 x + 0.8=0
⇒-0.0534 x + 0.8=0
⇒0.8=0.0534 x
⇒x=0.8/0.0534
x =14.98 (approx)
Now differentiating the expression again
=-0.0534
Since double derivative is negative , so
x=14.98 will be the point of Maxima.
The Kangaroo can go the maximum distance of 14.98 feet (approx)
and the height that can kangaroo go through=-0.0267×14.98×14.98+0.8×14.98
= -5.9914 +11.984
= 5.9925 feet
= 6 feet (approx)
So, X=Horizontal distance covered=14.98×2=29.96 feet,[∵ at x=14.98 it attains maximum height, So total distance Travelled by kangaroo will be two times of the distance covered that it has gone through to achieve maximum height.]⇒ The path is parabolic. = 30 feet (approx)
Y= Vertical distance covered= 5.9925=6 feet(approx)