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3 years ago

2a2 + 3b2 + a2 + b2

Mathematics

2 answers:

cestrela7 [59]3 years ago

8 0

Hope this helps! …………..

marshall27 [118]3 years ago

8 0

Answer:

Solution given:

2a2 + 3b2 + a2 + b2

adding like terms

2a²+a²+3b²+b²

3a²+4b² is a required answer.

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b. Carlos monthly office supply budget is $250. He needs to buy ink cartridges which cost $40 a piece. He will need to save at l

Tju [1.3M]

ANSWER

Find out the what is the range of ink cartridges he can buy and still have enough money left over for the reams of paper.

To proof

let us assume that the number of the ink cartridges buy be x.

As given

Carlos monthly office supply budget is $250.

He needs to buy ink cartridges which cost $40 a piece.

He will need to save at least $50 of his budget for reams of paper.

than the inequality is written in the form

$250 - 40 x \leq 50 \\ 40x = 200 \\ x\leq \frac{200}{40}$

x ≤ 5

the range of the ink cartridges he can buy be 0 ≤ x ≤ 5 when he saves

at least $50 of his budget for reams of paper.

Hence proved

7 0

4 years ago

What is the value of x in the equation x+x+2 divided by 4 equals 189.5

AlekseyPX

Answer: x = 94.5

Explanation: By using PEMDAS you can see there is no parentheses, exponents, or multiplication, so you start with dividing.
You can go ahead and combine the two x’s so you have 2x. So our equation now looks like:
2x + 2 ÷ 4 = 189
Divide first.
2 ÷ 4 = .5
Subtract from both sides.
.5 - 189.5 = 189
Divide by two to isolate the variable.
2x ÷ 189 = 94.5
so X =94.5
check your answer by plugging in the final number.
94.5 + 94.5 + 2 ÷ 4 = 189.5

4 0

4 years ago

Solve the inequality for u.<br> 7u - 32< - 3(6-3u)<br> Simplify your answer as much as possible.

Dmitry_Shevchenko [17]

Answer:

u > - 7

Step-by-step explanation:

7u - 32 < - 3(6-3u)

7u - 32 < - 18 + 9u

18-32 < - 7u + 9u

-14 < 2u

2u > - 14

u > - 7

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to 4 (9 + 7)

Bad White [126]

4(9+7) = 36+28 = 64

open the parentheses, then simplify.

8 0

2 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

Lerok [7]

Answer:

Q1 - D. f(x) = $x^4-9x^2-50x-150$

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Q14 - A. $7x+6+4x^{2}$

Step-by-step explanation:

Question 1:

We know that rational roots always occurs in pairs. So, the zeros of the function will be 5, -3, -1+3i, -1-3i

So, the factored form is $(x-5)(x+3)(x+1-3i)(x+1+3i)=0$

i.e. $(x^2-2x-15)(x+1-3i)(x+1+3i)=0$

i.e. $(x^3-x^2-3ix^2-17x+6ix-15+45i)(x+1+3i)=0$

i.e. $x^4-9x^2-50x-150=0$

Hence, the polynomial function is $f(x)=x^4-9x^2-50x-150$ .

Question 13:

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if $\frac{p}{q}$ is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, $\frac{p}{q}$ is a zero of $x^3-7x^2+9x-24=0$ . Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of $\frac{p}{q}$ are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = $4x^{2}$

Then, (f+g)(x) = f(x) + g(x) = 7x + 6 + $4x^{2}$

So, (f+g)(x) = $7x+6+4x^{2}$

6 0

4 years ago