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IRISSAK [1]
3 years ago
6

The sum of three consecutive numbers is 72. What are the smallest of these numbers?

Mathematics
2 answers:
lisov135 [29]3 years ago
3 0

let "a number" = x

(x) + (x + 1) + (x + 2) = 72

Simplify. Combine like terms

3x + 3 = 72

Isolate the x. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

3x + 3 (-3) = 72 (-3)

3x = 72 - 3

3x =  69

3x/3 = 69/3

x = 69/3

x = 23

23 is the smallest number

hope this helps

Ket [755]3 years ago
3 0

x , x+1, x+2

then  your sum would be   x + ( x + 1 ) + ( x + 2 ) = 72

so now just add em up

3x + 3 = 72

x = 69 / 3

x = 23

Hope this helps!

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Jayden wants to solve the equation n + 67 = 81. He writes the equation n + 67 - 67 = 81 - 67 to find the value of n. Will Jayden
Paladinen [302]
Hello there.

Question: <span>Jayden wants to solve the equation n + 67 = 81. He writes the equation n + 67 - 67 = 81 - 67 to find the value of n. Will Jayden get the correct answer using this equation? 

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In this part of the equation the 67 would cancel out.
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Solving the equation meant that he would have to subtract 67 from both sides.
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3 years ago
Sheryl's boss at always 21 pays a 5% commission on all sales. If Sheryl sells $140 worth of clothes, how much commission does sh
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The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is
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Answer:

a. At t = 5 s

a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}

b. At t = 10 s

a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}

c. At t = 20 s

a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}

Step-by-step explanation:

We know that the velocity function is given by

                                                   v(t)=\frac{105t}{6t+17}

Acceleration is the rate of change of velocity so we take the derivative of the velocity function with respect to time.

a(t)=\frac{dv}{dt}=\frac{d}{dt} (\frac{105t}{6t+17})

\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\105\frac{d}{dt}\left(\frac{t}{6t+17}\right)\\\\\mathrm{Apply\:the\:Quotient\:Rule}:\quad \frac{d}{{dx}}\left( {\frac{{f\left( x \right)}}{{g\left( x \right)}}} \right) = \frac{{\frac{d}{{dx}}f\left( x \right)g\left( x \right) - f\left( x \right)\frac{d}{{dx}}g\left( x \right)}}{{g^2 \left( x \right)}}

105\cdot \frac{\frac{d}{dt}\left(t\right)\left(6t+17\right)-\frac{d}{dt}\left(6t+17\right)t}{\left(6t+17\right)^2}\\\\105\cdot \frac{1\cdot \left(6t+17\right)-6t}{\left(6t+17\right)^2}\\\\a(t)=\frac{1785}{\left(6t+17\right)^2}

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a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}

b. At t = 10 s

a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}

c. At t = 20 s

a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}

3 0
3 years ago
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