Answer:
22.47
22.5 (simplified)
Step-by-step explanation:
22.47 = √(8^2 + 21^2)
Answer:
10 losses
Step-by-step explanation:
Here, we want to get the greatest possible number of games the team lost
Let the number of games won be x
Number drawn be y
Number lost be z
Mathematically;
x + y + z = 38
Let’s now work with the points
3(x) + 1(y) + z(0) = 80
3x + y = 80
So we have two equations here;
x + y + z = 80
3x + y = 80
The greatest possible number of games lost will minimize both the number of games won and the number of games drawn
We can have the following possible combinations of draws and wins;
26-2
25-5
24-8
23-11
22-14
21-17
21-17 is the highest possible to give a loss of zero
Subtracting each sum from 38, we have the following loses:
10, 8, 6, 4, 2 and 0
This shows the greatest possible number of games lost is 10
Answer:
2
Step-by-step explanation:
Answer:
Step-by-step explanation:
The multiplicative inverse of a complex number y is the complex number z such that (y)(z) = 1
So for this problem we need to find a number z such that
(3 - 2i) ( z ) = 1
If we take z = 
We have that
would be the multiplicative inverse of 3 - 2i
But remember that 2i = √-2 so we can rationalize the denominator of this complex number
Thus, the multiplicative inverse would be
The problem asks us to verify this by multiplying both numbers to see that the answer is 1:
Let's multiplicate this number by 3 - 2i to confirm:
Thus, the number we found is indeed the multiplicative inverse of 3 - 2i
Answer:
286
Step-by-step explanation:
multiply 13 by 22.
boom
