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3 years ago

9

Caroline wants to give 8 friends equal size packets of flower seeds to her friends. She has 1/2 pound of flower seeds. How much

will each packet of seeds weigh?

1 answer:

Katena32 [7]3 years ago

4 0

You just have to divide the 1/2 a pound by 8, or equivalently multiply by (1/8):

(1/2)*(1/8) = 1/16 of a pound

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What is the slope of the line that passes through the points (-8, -6)and (-18, 6) ? Write your answer in simplest form.

djyliett [7]

Answer:

-6/5

Step-by-step explanation:

You are going down 6 units and 5 units to the direction of the point you get .

5 0

3 years ago

Helpppppp pleaseeeeeee

NeX [460]

Answer: b)

Step-by-step explanation:

You can rule out A) and C), because you have to find area (no adding.)

To do this problem, you can individually multiply the estimated hieght and

width by 3 and then multiply together.

This is because there are 3 walls that each are 9 3/4 tall and 14 1/4 wide. To find total height and width, multiply by 3. Then find total area (lxw)

9 3/4 rounds to 10

14 1/4 rounds to 14

= 3 (10) x 3 (14)

D) is incorrect because you have to multiply each number by 3. (Or you can multiply by 6)

It is B)

4 0

2 years ago

Hello please pretyy

Juliette [100K]

It’s the first one. I think

6 0

3 years ago

Read 2 more answers

In a random sample of 8 people, the mean commute time to work was 33.5 minutes and the standard deviation was 7.2 minutes. A 95

Elina [12.6K]

Answer: Margin of error = 6.58

Confidence interval = (26.91, 40.08)

Step-by-step explanation:

Since we have given that

Sample size n = 8

Sample mean = 33.5 minutes

Population standard deviation = 9.5 minutes

At 95% confidence interval,

α = 0.05

t = 1.96

So, Margin of error is given by

$t\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{9.5}{\sqrt{8}}\\\\=6.58$

Confidence interval would be

Lower limit:

$\bar{x}-6.58\\\\=33.5-6.58\\\\=26.91$

Upper limit:

$\bar{x}+6.58\\\\=33.5+6.58\\\\=40.08$

Hence, the interval would be (26.91, 40.08)

But at standard deviation 7.2 minutes, the confidence interval was (27.5, 39.5)

Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.

3 0

3 years ago

If the number is divisible both 3 and 4, find the greatest common fact

madam [21]

12 | 3*4=12 therefor any number that is divisible by 3 and 4 is also divisible by 12

8 0

2 years ago