48. 40% of 80 is 32. 80-32=48. Which means there are 32 boys and 48 girls.
If you do in fact mean 
(as opposed to one of these being the derivative of 
at some point), then integrating twice gives
From the initial conditions, we find
Eliminating 
, we get
![C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)](https://tex.z-dn.net/?f=C_1%20%3D%20-%5Cdfrac%7B%5Cln%286%29%7D5%20%3D%20-%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%20%5Cimplies%20C_2%20%3D%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29)
Then
![\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20%3D%20%5Cln%7Cx%7C%20-%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%5C%2Cx%20%2B%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%7D)
F(x) = 22x + 33
g(x) = x² - 44x - 55
(g о f)(88) = (22(88) + 33)² - 44(22(88) + 33) - 55
(g о f)(88) = (1936 + 33)² - 44(1936 + 33) - 55
(g о f)(88) = (1969)² - 44(1969) - 55
(g о f)(88) = 3,876,961 - 86,636 - 55
(g о f)(88) = 2,790,325 - 55
(g о f)(88) = 3,790,270
Answer:
612
Step-by-step explanation:
The lateral surface area does not include the bases.
The bases are the triangles
We will add up the areas of the three rectangles
We have the two rectangles on the sides which are 17 by 13 and the rectangle on the bottom which is 17 by 10
17* 13 + 17*13 + 17*10 =612
