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shusha [124]
3 years ago
14

The side lengths of a triangle are 5,3,and 4. Is this a right triangle

Mathematics
1 answer:
Serggg [28]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

3, 4, 5 is a pythagorean triplet, meaning they satisfy the Pythagorean theorem.

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Plz help me giving brainliest
lianna [129]

Answer:

A. 80

Step-by-step explanation:

Count the first top half and you get 40 and you will know the bottom half is 40

which altogether is 80 or you can count the blocks one by one or count the blocks on the right side count the top blocks by five across.

V= l*w*h

V= 5*4*4

V= 80

Hope this Helps! :)

Have a nice day! :)

7 0
3 years ago
70% of x is 63. Write an equation to find the value of x, and solve the equation. What is the value of x?
melisa1 [442]

Answer:

70%of x = 63

70/100 × x = 63

x=63×100/70

x=90

Step-by-step explanation:

7 0
3 years ago
Solve for m: -14m = -28
Bingel [31]
Divide both sides by -14.

Answer:
m=2

6 0
3 years ago
Find the missing the coordinates. Tiles (2, 1) (2, -2) (-5, -5) (-1, -1) Pairs A(2, 5), B(6, 5), and C(6, 1) are three vertices
tensa zangetsu [6.8K]
1) <span>Pairs A(2, 5), B(6, 5), and C(6, 1)
point D
Dx=Cx-(Bx-Ax)=(6-(6-2))=2
Dy=Cy=1
</span>the coordinates of vertex D is (2,1)

2) 
Pairs <span>A(2, 3), B(7, 3), and C(7, -2)
</span>point D 
Dx=Cx-(Bx-Ax)=(7-(7-2))=2
Dy=Cy=-2
the coordinates of vertex D is (2,-2)

3) 
Pairs <span>A(-5, -1), B(1, -1), and C(1, -5)
</span>point D 
Dx=Cx-(Bx-Ax)=(1-(1+5))=-5
Dy=Cy=-5
the coordinates of vertex D is (-5,-5)

4) 
Pairs <span>A(-1, 4), B(7, 4), and C(7, -1)
</span>point D 
Dx=Cx-(Bx-Ax)=(7-(7+1))=-1
Dy=Cy=-1
the coordinates of vertex D is (-1,-1)
8 0
3 years ago
Read 2 more answers
Do you know how to do this question
Sever21 [200]

Percentage of the area shaded = 55%

Solution:

Perimeter of the square = 40 cm

Each side of the square = \frac{40}{4} = 10 cm

Area of the square = \text{side}^2

                               = 10²

                               = 100

Total area of the square = 100 cm²

The unshaded portion is two triangles.

Base of the smaller triangle = 10 cm – 7 cm = 3 cm

Height of the smaller triangle = 10 cm

Area of the smaller triangle = \frac{1}{2}\times \text{base}\times \text{height}

                                              $=\frac{1}{2}\times 3\times 10

Area of the smaller triangle = 15 cm²

Base of the larger triangle = 10 cm – 4 cm = 6 cm

Height of the larger triangle = 10 cm

Area of the larger triangle = \frac{1}{2}\times \text{base}\times \text{height}

                                              $=\frac{1}{2}\times 6\times 10

Area of the larger triangle = 30 cm²

Area of the shaded portion = Area of the square – Area of the smaller

                                                   triangle – Area of the larger triangle

                                              = 100 cm² – 15 cm² – 30 cm²

Area of the shaded portion = 55 cm²

Percentage of the area shaded = \frac{\text{Area of the shaded portion}}{\text{Total area of the square}}\times100\%

                                                    $=\frac{55}{100}\times100\%

Percentage of the area shaded = 55%

8 0
4 years ago
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