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3 years ago

8

Find the amount of time. I=$450, P=$2400, r=7.5%

1 answer:

Aliun [14]3 years ago

3 0

2.5 years
~You need to set this problem up in the I=PRT form. This should be your formula then, 450=2400(.075)(t). Then do 2400 times .075 and then times that by t which equals 180t. To get rid of that t then take 450 divided by 180 and you get 2.5. Remember when working with rates put them in decimal form also but your time in years.

I hope this helps you:)

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Three people whowork full time are working together on a project but their totaltime on the project is to be equivalent to that

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3 years ago

Consider the initial value problem:

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Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

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Alguien ayúdeme

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Hola Senor/Senorita!

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Step-by-step explanation: 40 / 4 = 10

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10 is less than 17 meaning that Danny is offering a better deal.

Hope this helps!

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