Answer: No, a<span>t high pressures, volume of a real gas does not compare with the volume of an ideal gas under the same conditions.
Reason:
For an ideal gas, there should not be any intermolecular forces of interaction. However, for real gases there are intermolecular forces of interaction like dipole-dipole and dipole-induced dipole. Further, at high pressures, molecules are close by. Hence, extend of these intermolecular forces is expected to be high. This results in decreases in volume of real gas. Thus, </span>volume of a real gas does not compare with the volume of an ideal gas under the same conditions.
Answer:
Standard form: (x+3)^2=1/2(y+3)
f(1) = 29
f(-1) = 5
Explanation:
The standard form of a parabola with a directrix that is horizontal is
(x-h)=4(P)(y-k)
Using the vertex form, find the vertex, foci, and the distance from the vertex to the focus or directrix.
It's easier to use the vertex form to plug in values for x.
f(1) = 2((1)+3)^2-3
f(1) = 29
f(-1) = 2((-1)+3)^2-3
f(-1) = 5
Answer:
single replacement reaction
Explanation:
This is a kind of single replacement reaction where you switch either cations or anions. Here you switched Ca for H and produced Cacl2 and H2 gas by itself.
We are going to use Avogadro's constant to calculate how many molecules of
carbons dioxide exist in lungs:
when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in
CO2 when the number of moles is 5 x 10^-2
number of molecules = moles of CO2 * Avogadro's number
= 5 x 10^-2 * 6.02 x 10^23
= 3 x 10^22 molecules
∴ There are 3 x 10^22 molecules in CO2 exist in lungs
D. The particles are tightly packed together