The SN1 reaction yields Entry field with incorrect answer two (number) products. This is because ______________________. Entry f
ield with incorrect answer The carbocation that forms can react with CH3OH from the top side of the molecule. The carbocation that forms can react with H2O from either the top or bottom side of the molecule. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from the top side of the molecule. The carbocation that forms can react with H2O from the bottom side of the molecule. The carbocation that forms can react with CH3OH from either the top or bottom side of the molecule. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from the bottom side of the molecule. The carbocation that forms can react with H2O from the top side of the molecule. The carbocation that forms can react with CH3OH from the bottom side of the molecule. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from either the top or bottom side of the molecule.
Four substitution products are obtained. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from either the top or bottom side of the molecule
Explanation:
An SN1 reaction usually involves the formation of a carbocation in the slow rate determining step. This carbocation is now attacked by a nucleophile in a subsequent fast step to give the desired product.
However, the product is obtained as a racemic mixture because the nucleophile may attack from the top or bottom of the carbocation hence both attacks are equally probable.
The attacking nucleophile in this case may be water or CH3OH
D is the best choice. Those percentages, are giving you the information about how concentrated are the solutions. As 0.015 is so concentrated, this solution will damage the structures more quickly
