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Katarina [22]
3 years ago
5

What is the percent CdSO4 by mass in a 1.00 m aqueous CdSO4 solution?

Chemistry
1 answer:
Svet_ta [14]3 years ago
3 0
I don't know but I'm wasting 5 seconds of your time you can't take back sorry
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#1: Which of the following is an exothermic reaction?
aleksandrvk [35]
<span>An exothermic reaction is one in which heat is released from the reagents into the ambient environment. Perhaps somewhat counterintuitively, condensation is in fact an example of such a reaction. During the process of the gas-to-liquid phase change, water goes from a higher-energy to lower-energy state of matter, and, as such, releases heat into the environment.</span>
5 0
3 years ago
Answer quickly i'm out of time !!!!!!
melamori03 [73]

Answer:

Option D. pH= 1.3 strong acid

Explanation:

From the question given:

The hydrogen ion concentration [H+] = 0.05 M

pH = —Log [H+]

pH = —Log 0.05

pH = 1.3

Since the pH lies between 0 and 7, the solution is acidic. Since the pH value is low, the solution is a strong acid

8 0
3 years ago
When naming ionic compounds the ______________ is named first.
grandymaker [24]
The answer is metal. Metals are always named first in ionic compounds, like KNO3 for example. I hope this helps!
7 0
3 years ago
When heated to 150 ºC, CuSO4.5 H2O loses its water of hydration as gaseous H2O. A 2.50 g sample of the compound is placed in a s
Katyanochek1 [597]

Answer:

Water pressure 0.5 atm

Total Pressure= 2.27  atm

Explanation:

To answer this problem, one has to realize that there are two processes that increase the temperature of the sealed vessel.

First, the dry air in the sealed vessel will be heated which will cause its pressure to increase and it can be determined by the equation:

P₁ x T₂   = P₂ x T₁  ∴  P₂ =  P₁ x T₂ / T₁

For the second process, we have an amount of n moles of water which will be released when the copper sulfate is heated. In this case, to determine the value of the the water gas we will use the gas law:

   PV = nRT  ∴ P =  nRT/V

n will we calculated from the quantity of sample.

2.50 g  CuSo₄ 5H₂O x  1 mol/ 249.69 g = 0.01 mol CuSo₄ 5H₂O

the amount water of hydration is

= 0.01 mol CuSo₄ 5H₂O * 5 mol H₂O / 1 mol CuSo₄ 5H₂O

= 0.05 mo H₂O

pressure of dry air at the final temperature,

P₂ = 1 atm x 500 K/ 300 K = 1.67 atm

Pressure of water :

P (H₂O) 0.05 mol x 0.08206 Latm/kmol x 500 K/ 4 L = 0.5 atm

∴ Total Pressure =  1.67 atm

H2O Pressure = 0.5 atm

5 0
3 years ago
How many kilojoules are equivalent to 10 joules?
miss Akunina [59]
1 Kj ------------- 1000 J
?? --------------- 10 J

10 x 1 / 1000 => 0.01 Kj
7 0
3 years ago
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