Total cost is $38.16
Multiply 36 by 0.06 (2.16)
Add 2.16 to 36 (38.16)
Answer: to make it easier
Step-by-step explanation:
well 9+3=12 but taking 1 from the three and making ten then adding 2 is easier
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
I think you mean roll a die. To do this you would find the number of non-even numbers and divide that number by the total amount of numbers on the die. On a normal six-sided die these numbers would be 1,3,and 5, so your probability of not rolling an even number would be 50%