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s344n2d4d5 [400]
3 years ago
8

Find laplace transform of t+t^2 +t^3

Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0

Recall that

L_s\left\{t^n\right\} = \dfrac{n!}{s^{n+1}}

where L_s\left\{y(t)\} is the Laplace transform of <em>y(t)</em> into the <em>s</em>-domain.

Then you have

L_s\left\{t+t^2+t^3\right\} = \dfrac{1!}{s^{1+1}} + \dfrac{2!}{s^{2+1}} + \dfrac{3!}{s^{3+1}} = \boxed{\dfrac1{s^2} + \dfrac2{s^3} + \dfrac6{s^4}}

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3 years ago
Anyone have a answer for this?
LiRa [457]

Answer:

36.1 meters

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I'll choose to look at the bottom triangle in this case

30 is already there, and the other leg should be 20. Knowing this, we can plug these into the pythagorean theorem.

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