Question

Factor 0.04m 2 - n 2. (0.2n - m)(0.2n + m) (0.2m - n)(0.2m - n) (0.2m - n)(0.2m + n)

Answer 1

Answer:

$0.04m^2-n^2=(0.2m-n)(0.2m+n)$

Step-by-step explanation:

We have to factorize the given expression i.e $0.04m^2-n^2$

According to the identity of $a^2-b^2$

$a^2-b^2=(a-b)(a+b)$

Given expression is

$0.04m^2-n^2=(0.2m)^2-n^2\\\\a=0.2m, b=n\\\\implies\\(0.2m-n)(0.2m+n)$

Hence, $0.04m^2-n^2=(0.2m-n)(0.2m+n)$

Answer 2

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0.04m² - n²

(0.2m)² - n²

(0.2m + n)(0.2m -  n)
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