Hello :
hello : <span>
1 ) if : x</span>ـــــــ> ± ∞
<span>
limf(x) = b ....(b</span>∈R) so : y=b is the equation of
the line horizontal asymptote.
<span>
2) if : x</span>ـــــــ>
a ...(a∈R)<span>
limf(x) = ± ∞
<span>so : x=a is the equation of the
line vertical asymptote.</span></span>
<span><span>hint : in this exercice : a = 2 or a = 7 but : b=2</span></span>
Answer:
None
Step-by-step explanation:
None of these, but
so if 64 is an option than that's the correct option

Answer:
Search this up on google to find out what the answer is because no one is going to know how to do it.
Answer:
∠BAD=20°20'
∠ADB=34°90'
Step-by-step explanation:
AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.
Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus
∠BOD+∠BDO+∠DBO=180°
∠BDO+∠DBO=180°-110°20'=69°80'
∠BDO=∠DBO=34°90'
So ∠ADB=34°90'
Angles BOD and BOA are supplementary (add up to 180°), so
∠BOA=180°-110°20'=69°80'
In right triangle ABO,
∠ABO+∠BOA+∠OAB=180°
90°+69°80'+∠OAB=180°
∠OAB=180°-90°-69°80'
∠OAB=20°20'
So, ∠BAD=20°20'