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dem82 [27]
2 years ago
10

1. Find the missing side length.

Mathematics
2 answers:
Anon25 [30]2 years ago
8 0
The first one is b=75the second one is c= 15Hope this helps!

julsineya [31]2 years ago
4 0
Number 2 is 75m using Pythagoras theorem
Number 1 is 15in using Pythagoras theorem also
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Find a formula for a function that has vertical asymptotes x = 2 and x = 7 and horizontal asymptote y = 2.
Pie
Hello : 

 

hello : <span>
1 ) if : x</span>ـــــــ> ± ∞  <span>
 limf(x)   = b     ....(b</span>∈R)     so : y=b is the equation of the line horizontal asymptote.

<span>
2) if : x</span>ـــــــ> a ...(a∈R)<span>
 limf(x)   = ± ∞  
<span>so : x=a is the equation of the line vertical asymptote.</span></span>

<span><span>hint : in this exercice : a = 2 or a = 7  but : b=2</span></span>

6 0
3 years ago
Which is a perfect square?<br>61<br>62<br>63<br>65​
Morgarella [4.7K]

Answer:

None

Step-by-step explanation:

None of these, but \sqrt{64}=8 so if 64 is an option than that's the correct option

\sqrt{61} =7.81 \\\sqrt{62}=7.87\\\sqrt{63} =7.93\\\sqrt{65} =8.06

3 0
3 years ago
The endpoints of PQ are (4,1) and Q(4,8)
tatuchka [14]

Answer:

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5 0
3 years ago
AB is tangent to the circle k(O) at B, and AD is a secant, which goes through center O. Point O is between A and D∈k(O). Find m∠
drek231 [11]

Answer:

∠BAD=20°20'

∠ADB=34°90'

Step-by-step explanation:

AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.

Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus

∠BOD+∠BDO+∠DBO=180°

∠BDO+∠DBO=180°-110°20'=69°80'

∠BDO=∠DBO=34°90'

So ∠ADB=34°90'

Angles BOD and BOA are supplementary (add up to 180°), so

∠BOA=180°-110°20'=69°80'

In right triangle ABO,

∠ABO+∠BOA+∠OAB=180°

90°+69°80'+∠OAB=180°

∠OAB=180°-90°-69°80'

∠OAB=20°20'

So, ∠BAD=20°20'

5 0
3 years ago
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Help please, its pre-pre algebra
Lyrx [107]
8/74 l think it that
5 0
2 years ago
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