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guapka [62]
3 years ago
5

In ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. Find the measure of ∠J to the nearest degree.

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.

First of all, we will draw a triangle as shown in the attachment.

We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.

We know that sine relates opposite side of right triangle to hypotenuse.

\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}

\text{sin}(\angle J)=\frac{22}{54}

Using inverse sine or arcsin, we will get:

\angle J=\text{sin}^{-1}(\frac{22}{54})

\angle J=24.042075905756^{\circ}

Upon rounding to nearest degree, we will get:

\angle J\approx 24^{\circ}

Therefore, the measure of angle J is approximately 24 degrees.

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