What is 3.9 x 10^33 x 1.55 x 10^7
2 answers:
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One way would be to find the distance from the point to the center of the circle and compare it to the radius
for
the center is (h,k) and the radius is r
and the distance formula is
distance between
and 
is
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
the radius is
center is (-2,3)
find distance between (8,4) and (-2,3)
≈4.2
≈10.04
do r<D
(8,4) is outside the circle
for
the center is (h,k) and the radius is r
and the distance formula is
distance between
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
the radius is
center is (-2,3)
find distance between (8,4) and (-2,3)
do r<D
(8,4) is outside the circle
First, I would multiply the last two fractions because they're smaller and easier to work with:
Now that we've simplified it, we could multiply these terms and simplify. An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:
We can now multiply these terms:
The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>