Hagsua jejxhs didwjejw 373 jejsjsjab shanahabsbxzbahabss shahsbdgs a hansbaaq shhshsna hdjehsjss bxxhzbzb jshsbdjsjwnxnxjjd jxnsjxsnhazndk nxizjshjxgxsjsshzhnsjsjznnzn jxkziissjjsjs disks kiz icjjxk iDisks Jiangxi. Sbsujsnahahhjsnsb. Shaman shdbsbsbba w subs babe Ben a shave. S. Shhshshqjv shahhshzhxhd
Answer:
C. an= -3+ (n - 115)
Step-by-step explanation:
hope it help
Answer:
9.89 m
Step-by-step explanation:
AC is the hypotenuse (H)
x is the opposite (O)
O and H are in sine
sin=O/H
H=O/sin
H=7.9/sin(53)
=9.89187169943418
3 SF
9.89 m
Answer:
8.75cm²
Step-by-step explanation:
First we need to find the angle subtended by the arc
L = theta/360 * 2pir
3.5 = theta/360 * 2*3.14(5)
3.5 = theta/360 * 31.4
theta/360 = 3.5/31.4
theta/360 = 0.11146
theta = 0.11146 * 360
theta = 40.13 degrees
Area of the sector = theta/360 * pir^2
Area of the sector = 40.13/360 * 3.14*25
Area of the sector = 40.13/360 * 78.5
Area of the sector = 8.75cm
Hence the area of the sector is 8.75cm²
Are you sure this is the COMPLETE problem?
