Question

A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?

Answer 1

L x W = 60
2(L + W) = 32
 L + W = 16
 L = 16 - W

substitute  L = 16 - W into L x W = 60
L x W = 60
(16 - W) x W = 60
16W -W^2 = 60
W^2 - 16W + 60 = 0
(W - 6)(W - 10) = 0
W - 6 = 0; W = 6
W - 10 = 0; W = 10

answer
Length = 10 m and Width = 6 m

Answer 2

6 and 10 because 6 times 10 is 60 and 6 plus 6 plus 20 plus 10 is 32