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Alik [6]
3 years ago
7

A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?

Mathematics
2 answers:
Virty [35]3 years ago
6 0
L x W = 60
2(L + W) = 32
 L + W = 16
 L = 16 - W

substitute  L = 16 - W into L x W = 60
L x W = 60
(16 - W) x W = 60
16W -W^2 = 60
W^2 - 16W + 60 = 0
(W - 6)(W - 10) = 0
W - 6 = 0; W = 6
W - 10 = 0; W = 10

answer
Length = 10 m and Width = 6 m
SOVA2 [1]3 years ago
4 0
6 and 10 because 6 times 10 is 60 and 6 plus 6 plus 20 plus 10 is 32
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Factor 3/4 out of 3/4z + 6
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\frac{3}{4} z + 6 =  \frac{3}{4} (z +  8  )


EXPLANATION

We want to factor
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The first term is already having a factor of
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\frac{3}{4} z + 6 =  \frac{3}{4} z +  \frac{3}{4}  \times  \frac{6}{ \frac{3}{4} }


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\frac{3}{4} z + 6 =  \frac{3}{4} (z +  6 \div  \frac{3}{4}  )




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\frac{3}{4} z + 6 =  \frac{3}{4} (z +  8  )


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