Answer:
From the information we can conclude that the triangle is a isosceles triangle.
First, we can calculate the hypotenuse by using pythagorean theorem:
√(6² + 6²) = √(36 + 36) =√64 = 8 (cm)
To calculate the area of the triangle, we first need to know the height of it.
Since this is a isosceles triangle, the altitude (which is also the height) will also be the median of that triangle.
Then we also have a 90° angle, this triangle is also a right triangle, and in right triangle, the median will equal half of the hypotenuse.
From the reasoning above, we can now calculate the height of the triangle:
8/2 = 4(cm)
The area of the triangle should be:
S = hb/2 = (4 . 6)/2 = 12 (cm²)
Answer:
no, i dont think so because parralel lines are this
Step-by-step explanation:
hope it helps
Answer:
1.5
Step-by-step explanation:
Here you go. I hope this will help
Answer:
If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.
Step-by-step explanation:
Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.
Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

When we use this to replace the 't" in the displacement formula, we et:

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)
And we can also answer the question about time, since given the same initial velocity
, the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)