1st one is x=5
2nd one is x=-15
Pls mark brainliest
Answer:
So for a hint to help you...when you are looking at a triangle on a 180 degree line, each angle adds up to 180 degrees. So for example, on #9 on the top of the triangle, one of the angles is 49 degrees so you want to subtract that from 180 ( 180 - 49 = X ) ( X = angle 1 and 2 ) so angle 1 and 2 added together equals X. In this case, ( X = 131 degrees ) Every triangle equals 180 degrees too. So since this angle has 3 different angles on the line, you can do the rest of the problems and come back to these because you can subtract angle 4 and 73 to get angle 2.
(still on #9) Angle 3, as you can see only has one other number beside it (73) so it makes this one very easy. ( 180 - 73 = X ) ( X = 107 ) <u>Angle 3 = 107 degrees</u>
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Angle 5. Subtract the 49 above angle 5 from 180 and the result will be angle 5. ( 180 - 49 = X ) ( X = Angle 5 ) <u>X/angle 5 = 131.</u>
Now you can get angle 4, which gives you angle 2 and 1. ( 180 - 131 = Angle 4 ) <u>(Angle 4 = 49)</u>
Angle 2. In the triangle, we have 73 degrees, and 49 degrees. So the equation for this one is, ( 180 - 73 - 49 = Angle 2 ) ( Angle 2 = 58 )
Angle 1. On this line, we have 49 degrees and 2=58 degrees. ( 180 - 58 - 49 = Angle 1 ) <u>( Angle 1 = 73 )</u>
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Lastly, Angle 3. The side of this triangle will also equal 180, just like the top line. Angle 1 = 73 degrees so as you now know, subtract that from 180 and get angle 3. ( 180 - 73 = Angle 3 ) <u>(Angle 3 = 107 )</u>
<u></u>
1: 73 degrees
2: 58 degrees
3: 107 degrees
4: 49 degrees
5: 131 degrees
I know this is a lot to read, but I really hope I explained it to where you can understand it now.
X=number of games played
just do simple multiplication
remember that orded pairs are (x,y)
x=5
y=0.50(5)+3
y=2.5+3
y=5.5
orderd pair is (5,5.5)
x=10
y=0.50(10)+3
y=5+3
y=8
ordered pair is (10,8)
x=20
y=0.50(20)+3
y=10+3
y=13
ordered pair is (20,13)
(5,5.5)
(10,8)
(20,13)
Answer:
2.7%
Step-by-step explanation:
Since the probability of having and accident or exceed the deductible does not depend on the color of the car, the events are independent.
Recall that if two events A and B with probabilities P(A), P(B) of occurrence are independent, then
P(A ∩ B) = P(A)P(B)
There is a 300/1000 = 0.3 probability of choosing a random car. So, if the actuary randomly picks a claim from all claims that exceed the deductible,the probability that the claim is on a red car is
0.3*0.10*0.9 = 0.027 or 2.7%
