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True [87]
3 years ago
6

A car can drive 476 miles on 14 gallon

Mathematics
1 answer:
Degger [83]3 years ago
8 0
What is the question?
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This is part one of the problem I’m going to post the part two right after this
frez [133]

Answer:

no

Step-by-step explanation:

3 0
3 years ago
Suppose that the number of bacteria in a certain population increases according to an exponential growth model. A sample of 2600
melisa1 [442]

Answer: There is 3.994% continuous growth rate per hour.

Step-by-step explanation:

Since we have given that

Initial bacteria = 2600

After two and a half hours,

Number of bacteria = 2873

We need to find the continuous growth rate per hour.

As we know the equation for continuous growth rate per hour.

y=y_0e^{rt}\\\\2873=2600e^{2.5r}\\\\\dfrac{2873}{2600}=e^{2.5r}\\\\1.105=e^{2.5r}\\\\\text{Taking log on both the sides}\\\\\ln 1.105=2.5r\\\\0.0998=2.5r\\\\r=\dfac{0.0998}{2.5}\\\\r=0.0399\times 100\\\\r=3.994\%

Hence, there is 3.994% continuous growth rate per hour.

3 0
4 years ago
We did not find results for: A measure of​ malnutrition, called the​ pelidisi, varies directly as the cube root of a​ person's w
asambeis [7]
\bf \qquad \qquad \textit{double proportional variation}\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\

\bf \begin{cases}
p=pedalisi\\
w=weight\\
s=\textit{sitting height}
\end{cases}\quad 
\begin{array}{llll}
%pelidisi, varies directly as the cube root of a​ person's weight in grams and inversely as the​ person's sitting height in centimeters.
\textit{pelidisi varies directly}\\
\textit{as cube root of weight}\\
\textit{and inversely to }\\
\textit{sitting height}
\end{array}\implies p=\cfrac{k\sqrt[3]{w}}{s}\\\\
-------------------------------

\bf \textit{we know that }
\begin{cases}
w=48,820\\
s=78.7\\
p=100
\end{cases}\implies 100=\cfrac{k\sqrt[3]{48820}}{78.7}
\\\\\\
100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k
\\\\\\
thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}
\\\\\\
\textit{now, what is \underline{p} when }
\begin{cases}
w=54,688\\
s=72.6
\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.
3 0
4 years ago
I Reaally Need Help If You Wamt Ill Eve Go Over 100 Points
Pani-rosa [81]
(a) y = 2x + 3
(b) (1,5), (3,3); y = 3x + 3      5 = m1 + b, 3 = m3 + b
(c) coincident i believe, because it is not independent or inconsistent
(d) 2x + 3 = 3x + 3
     (-2x)(-3)  (-2x)(- 3)
0 = -2x
x = 0

hope this helps
5 0
3 years ago
Read 2 more answers
1. The product of two consecutive integers <br> is 20. Find the values of these integers.
gulaghasi [49]
First find the factors of 20
1 & 20
2 & 10
4 & 5
-1 & -20
-2 & -10
-4 & -5

Now find the pairs that have a difference of 1

-4 & -5
4 & 5
4 0
3 years ago
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