Answer:
P(n)= p0 + 11(n)
Where p0= population of week 0
P(n) = population of n weeks
n= number of weeks
Step-by-step explanation:
Population of beetles in Week 0= 6
Population of beetles in Week 7= 83
From week 0 to week 7 there are 8 weeks.
But subtracting population of week 0 from population of week 7 gives
= 83-6
= 77
After the subtraction, we have 7 weeks remaining.
Dividing the remaining population by the number of weeks remaining
=77/7
= 11
For n number of weeks, population p of beetles
P(n)= p0 + 11(n)
Where p0= population of week 0
P(n) = population of n weeks
n= number of weeks
Letters used to represent values or unknown quantities that
can change or vary. One example of an algebraic expression
is 3x – 4. Notice the variable,
Answer:
9
15
24
33
Step-by-step explanation:
I hope this right
Answer:
happy birthday may god bless you
Answer:
This is 0.14 to the nearest hundredth
Step-by-step explanation:
Firstly we list the parameters;
Drive to school = 40
Take the bus = 50
Walk = 10
Sophomore = 30
Junior = 35
Senior = 35
Total number of students in sample is 100
Let W be the event that a student walked to school
So P(w) = 10/100 = 0.1
Let S be the event that a student is a senior
P(S) = 35/100 = 0.35
The probability we want to calculate can be said to be;
Probability that a student walked to school given that he is a senior
This can be represented and calculated as follows;
P( w| s) = P( w n s) / P(s)
w n s is the probability that a student walked to school and he is a senior
We need to know the number of seniors who walked to school
From the table, this is 5/100 = 0.05
So the Conditional probability is as follows;
P(W | S ) = 0.05/0.35 = 0.1429
To the nearest hundredth, that is 0.14
