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Savatey [412]
1 year ago
13

A number cube is rolled three times. An outcome is represented by a string of the sort OEE (meaning an odd number on the first r

oll, an even number on the second roll, and an even number on the third roll). The outcomes are listed in the table below. Note that each outcome has the same probability.

Mathematics
1 answer:
Kryger [21]1 year ago
7 0

The probability of occurrence for the events A, B and C is; 1/4.

<h3>What is the probability of occurrence of.the described events?</h3>

For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;

Event A = 2/8 = 1/4.

For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;

Event B = 2/8 = 1/4.

For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;

Event C = 2/8 = 1/4.

Read more on probability;

brainly.com/question/251701

#SPJ1

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The solution is x \geq 13.

Solution:

Given inequality:

7 x \geq 91

Divide by 7 on both sides.

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x \geq 13

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The image of the graph is attached below.

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2 years ago
Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.​
sergiy2304 [10]

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2 real solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0

Discriminant: b² - 4ac

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Step-by-step explanation:

<u>Step 1: Define</u>

x² - 6x - 10 = 0

<u>Step 2: Identify Variables</u>

<em>Compare quadratic.</em>

x² - 6x - 10 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = -10

<u>Step 3: Find Discriminant</u>

  1. Substitute in variables [Discriminant]:                                                            (-6)² - 4(1)(-10)
  2. [Discriminant] Evaluate exponents:                                                                36 - 4(1)(-10)
  3. [Discriminant] Multiply:                                                                                    36 + 40
  4. [Discriminant] Add:                                                                                          76

This tells us that our quadratic has 2 real solutions.

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Step-by-step explanation:

look at image for step by step

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