A candle burns down at the rate of 0.5 inches per hour. The original height of the candle was 6 inches.
1 answer:
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Answer:
The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.
Step-by-step explanation:
Given : The position of an object along a vertical line is given by , where s is measured in feet and t is measured in seconds.
To find : What is the maximum velocity of the object in the time interval [0, 4]?
Solution :
The velocity is rate of change of distance w.r.t time.
Distance in terms of t is given by,
Derivate w.r.t. time,
It is a quadratic function so its maximum is at vertex of the function.
The x point of the function is given by,
Where, a=-3, b=6 and c=7
As 1 lie between interval [0,4]
Substitute t=1 in the function,
Th maximum velocity is 10 ft/s.
Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.
Answer:
Option 3 -
Step-by-step explanation:
Given : Perpendicular to the line ; containing the point (4,4).
To Find : An equation for the line with the given properties ?
Solution :
We know that,
When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.
Slope of the equation
Converting into slope form ,
Where m is the slope.
The slope of the equation is
The slope of the perpendicular equation is
The required slope is
The required equation is
Substitute point (x,y)=(4,4)
Substitute back in equation,
Therefore, The required equation for the line is
So, Option 3 is correct.
Step-by-step explanation:
the answer is the image above
