What is the best classification of –4/5 in the real number system?
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The margin of error is 0.137 and the confidence interval for the population proportion is (0.443, 0.717).
<h3>What is the margin of error(MOE)?</h3>It is defined as an error that provides an estimate of the percentage of errors in real statistical data.
The formula for finding the MOE:
Where Z is the z-score at the confidence interval
s is the standard deviation
n is the number of samples.
We have:
n = 50, X = 29,
Estimate point p = 29/50 = 0.58
q = 1-p = 1-0.58 = 0.42
Z at 0.05/2 (95% confidence interval) = 1.96
After calculating:
MOE = 0.137
Confidence interval will be: (p - MOE, p+MOE)
= (0.58-0.137, 0.58+0.137)
= (0.443, 0.717)
Thus, the margin of error is 0.137 and the confidence interval for the population proportion is (0.443, 0.717).
Learn more about the Margin of error here:
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First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:
This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is 135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is 33 students.
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:
This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is 135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is 33 students.