Answer:
cytoplasm is A, Dna is C, and nucleas is B
Explanation:
Answer:
Depending on the
value of
, the cell potential would be:
, using data from this particular question; or- approximately
, using data from the CRC handbooks.
Explanation:
In this galvanic cell, the following two reactions are going on:
- The conversion between
and
ions,
, and - The conversion between
and
ions,
.
Note that the standard reduction potential of
ions to
is higher than that of
ions to
. Alternatively, consider the fact that in the metal activity series, copper is more reactive than silver. Either way, the reaction is this cell will be spontaneous (and will generate a positive EMF) only if
ions are reduced while
is oxidized.
Therefore:
- The reduction reaction at the cathode will be:
. The standard cell potential of this reaction (according to this question) is
. According to the 2012 CRC handbook, that value will be approximately
.
- The oxidation at the anode will be:
. According to this question, this reaction in the opposite direction (
) has an electrode potential of
. When that reaction is inverted, the electrode potential will also be inverted. Therefore,
.
The cell potential is the sum of the electrode potentials at the cathode and at the anode:
.
Using data from the 1985 and 2012 CRC Handbook:
.
I believe the third choice is correct.
This can be proven by the fact that to find the molar mass of a compound, you simply add the molar masses of all the atoms within the compound
Hope this helps
Answer:
3.07 Cal/g
Explanation:
Step 1: Calculate the heat absorbed by the calorimeter
We will use the following expression.
Q = C × ΔT
where,
- C: heat capacity of the calorimeter (37.60 kJ/K = 37.60 kJ/°C)
- ΔT: temperature change (2.29 °C)
Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ
According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.
Step 2: Convert 86.1 kJ to Cal
We will use the conversion factor 1 Cal = 4.186 kJ.
86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal
Step 3: Calculate the number of Cal per gram of candy
20.6 Cal/6.70 g = 3.07 Cal/g
I think the answer is : 1