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algol [13]
3 years ago
8

Someone help meeee please

Chemistry
1 answer:
lana [24]3 years ago
3 0
2. Oxygen because it has more mass
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How many Liters are there in 51. 300 cm? (11 = 1000 cm)
Black_prince [1.1K]

Answer:

4,572.67

Explanation:

11 divided by 1000= 90.90

44= 11x

x=4

4 x 11= 4000

44-51.300=6.300

6.300 x 90.90=572.67

4000 + 572.67 = the answer

7 0
3 years ago
You are practicing classification by sorting pictures into groups based on the characteristics of the kingdoms. While you are so
posledela

Answer: D

Explanation: fungi kingdom is Hetrotropiv and is unicellular

7 0
3 years ago
A substance is made up of 78.57% boron and 21.43% hydrogen. What is the formula for this compound?
zhuklara [117]

Anlllllllllllllllllll

Explanation:

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7 0
2 years ago
Read 2 more answers
What is the mass of 0.73 moles of AgNO3?
love history [14]

Answer:

124 g (3 sig figs)

or

124.011 g (6 sig figs

Explanation:

Step 1: Calculate g/mol for AgNO₃

Ag - 107.868 g/mol

N - 14.01 g/mol

O - 16.00 g/mol

107.868 + 14.01 + 16.00(3) = 169.878 g/mol

Step 2: Multiply 0.73 moles by molar mass

0.73 mol (169.979 g/mol)

124 grams of AgNO₃

6 0
3 years ago
What is the frequency of electromagnetic radiation needed to excite an electron in a hydrogen atom from the n = 3 orbit to the n
Andreas93 [3]

The energy of 800 milimoles of photons is 1.38 * 10^-19 J.

<h3>What is excitation of electrons?</h3>

We know that an electron can move from a lower to higher energy level according to the formula;

1/λ = RH(1/ni^2 - 1/nf^2)

RH = 1.097 * 10^7m-1

ni = 3

nf = 6

Thus;

1/λ = 1.097 * 10^7(1/3^2 - 1/6^2)

1/λ = 1.097 * 10^7(1/9 - 1/36)

1/λ = 1.097 * 10^7(0.11 - 0.03)

λ =1.14 * 10^-6 m

v = λf

f = v/λ

f = 3 * 10^8 m/s/1.14 * 10^-6 m

f = 2.6 * 10^14 Hz

Now

E = hf

E= 6.63 * 10^-34 * 2.6 * 10^14 Hz

E = 1.72 * 10^-19 J

Now;

1 mole of photons has 1.72 * 10^-19 J of energy

800 * 10^-3 moles of photons has 800 * 10^-3 moles * 1.72 * 10^-19 J/ 1 mole

= 1.38 * 10^-19 J

Learn more about energy of photons:brainly.com/question/2393994

#SPJ1

5 0
2 years ago
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