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valina [46]
3 years ago
13

Through:(3,-1),slope=-1

Mathematics
1 answer:
Wewaii [24]3 years ago
5 0

Answer:

y = -x + 2

Step-by-step explanation:

Use the point-slope formula y - k = m(x -h):

y - [-1] = -1(x - 3), or

y + 1 = -x + 3, or

y = -x + 2

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4 0
3 years ago
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She spent 200 minutes
6 0
2 years ago
In general, as sample size increases Group of answer choices the standard error increases in size the standard error decreases i
Vikki [24]

Answer:

98.9

Step-by-step explanation:

98.9

4 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
marissa [1.9K]

Answer:

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

( x = 30 * 0.93... = ( About ) 28.01t

This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

<u><em>These are are parametric equations</em></u>

5 0
3 years ago
a ball is shot straight upward. with it's height, in feet, after t seconds given by the function f(t)=-16t^2+192t. Find the aver
jekas [21]

ANSWER

80  {ms}^{ - 1}

EXPLANATION

The average velocity of the ball is the rateof displacement over the total time.

The height of the ball, in feet, after t seconds is given by the function:

f(t)=-16t^2+192t

At time t=1, the height of the ball is

f(1)=-16(1)^2+192(1)

f(1)=-16+192 = 176ft

At time t=6, the height of the ball is

f(6)=-16(6)^2+192(6)

f(6)=-16(36)+192(6)

f(6)=-576+1152 = 576

The average velocity

=  \frac{f(6) - f(1)}{6 - 1}

=  \frac{576- 176}{6 - 1}

=  \frac{400}{5}

= 80  {ms}^{ - 1}

7 0
3 years ago
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