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larisa86 [58]
3 years ago
7

A photograph is 18 cm by 12 cm. It is to be surrounded by a frame of uniform width whose area is equal to that of the photograph

. Find the width of the frame
Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

Width of the frame = 54 cm

Step-by-step explanation:

  1. Find area of the frame = l*h = 18*12 = 216 cm
  2. Area of the frame = area of the photograph = 216 cm
  3. Use the given fact, photograph is surrounded by a frame of uniform width = all sides are equal.
  4. width of the frame = 216/4 = 54

<u>Source</u><u>: TutorEye</u>

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Step-by-step explanation:

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3 years ago
Please help me with this question with full solutions!!!
Novay_Z [31]

Answer: Choice C

x/w and z/(y+v)

======================================================

Explanation:

All answer choices have that first fraction with a denominator of w. This implies that AB = w is the hypotenuse. This only applies to triangle ABD.

Focus on triangle ABD. It has an opposite leg of AD = x, when the reference angle is ABD (or angle B for short).

So we can say sin(ABD) = opposite/hypotenuse = AD/AB = x/w

x/w is one of the answers

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Also note how y+v is the same for each denominator in the second fraction. y+v is the hypotenuse of triangle ABC. When the reference angle is ABD (aka angle ABC), the opposite side of this same triangle is AX = z

Therefore,

sin(ABD) = sin(ABC) = opp/hyp = AC/BC = z/(y+v)

z/(y+v) is the other answer

Side note: triangle ACD is not used at all.

5 0
3 years ago
Read 2 more answers
Wendy goes to the gym every 4 days and swims every 6 days. If she went to the gym and swam today, in how many days will she do b
Mice21 [21]

In 12 days, Wendy will do the both again.

Step-by-step explanation:

Given,

Wendy goes to gym every 4 days

Wendy swims every 6 days

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4 = 4,8,12,16,20,....

6 = 6,12,18,24,.....

Therefore;

The least common multiple of 4 and 6 is 12.

Thus,

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Keywords: multiples, LCM

Learn more about multiples at:

  • brainly.com/question/10196212
  • brainly.com/question/1021953

#LearnwithBrainly

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3 years ago
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If the perimeter is 168 and the width is 6 feet longer than thr length what are the dimensions
Ksenya-84 [330]

\bf \textit{perimeter of a rectangle}\\\\ P=2(L+w)~~ \begin{cases} L=length\\ w=width\\ ----------\\ P=168\\ w=\stackrel{\textit{6 feet longer than L}}{L+6} \end{cases}\implies 168=2(L+\stackrel{w}{L+6}) \\\\\\ 84=2L+6\implies 78=2L\implies \cfrac{78}{2}=L\implies \boxed{39=L} \\\\\\ w=39+6\implies \boxed{w=45}

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3 years ago
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