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valina [46]
3 years ago
5

3(x-4) = x + 14 How do you solve this equation

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

x=13

Step-by-step explanation:

you have to isolate the variable

3(x-4)=x+14

distribute

3x-12=x+14

subtract 14 from each side

3x-26=x

subtract 3x from each side

-26=-2x

divide each side by -2

13=x

flip sides

x=13

hope this helps!!! :)

Ainat [17]3 years ago
3 0

Answer:

X= 8.6666

Step-by-step explanation:

First multiply ehat is on the outside by the inside.

3×X=3x

3×-4= -12.

Now you have 3X-12= X+14

First add -12 to 14.

Your goal is to get all the numbers on one side and the letters on the other side.

12+14=26.

Now you have 3X=26

To get the X by itself divide 3 on both sides.

X÷3= X

26÷3=8.6666

So your answer is X=8.6666

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Answer:

m = 1

Step-by-step explanation:

slope = (y₂-y₁)/(x₂-x₁)

m = (4 - -1) / 1 - -4) = 5/5 = 1

5 0
3 years ago
Wen takes a job with a starting salary of $100,000 for the first year. she earns a 3% increase each year. what does s5 represent
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S_{n} = \frac{ a_{1}(1- r^{n})  }{1-r} a_{1} = 100000, r=1.03, n=5
S_{5} = \frac{100000(1- 1.03^{5}) }{1-1.03} = \frac{100000(-.159)}{-.03} =530,000

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3 years ago
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Step-by-step explanation:

7 0
2 years ago
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Please solve this<br> (Rational numbers 8th grade)
pochemuha

                                        Question # 1

Answer:

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}

Step-by-step explanation:

Given the expression

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}

=-\frac{2}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}           ∵  \frac{-2}{3}\times \frac{3}{5}=-\frac{2}{5}

=-\frac{2}{5}+\frac{1}{4}                        ∵   \frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=\frac{1}{4}

\mathrm{Least\:Common\:Multiplier\:of\:}5,\:4:\quad 20

=-\frac{8}{20}+\frac{5}{20}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{-8+5}{20}

\mathrm{Add/Subtract\:the\:numbers:}\:-8+5=-3

=\frac{-3}{20}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

=-\frac{3}{20}

Therefore,

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}

                                               Question # 2

Answer:

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}

Step-by-step explanation:

Given

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}

=-\frac{6}{35}-\frac{1}{6}\times \frac{3}{2}\times \frac{2}{5}\times \frac{1}{14}          ∵    \frac{2}{5}\times \frac{-3}{7}=-\frac{6}{35}

=-\frac{6}{35}-\frac{1}{140}         ∵   \frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=\frac{1}{140}

\mathrm{Least\:Common\:Multiplier\:of\:}35,\:140:\quad 140

=-\frac{24}{140}-\frac{1}{140}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{-24-1}{140}

\mathrm{Subtract\:the\:numbers:}\:-24-1=-25

=\frac{-25}{140}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

=-\frac{25}{140}

\mathrm{Cancel\:the\:common\:factor:}\:5

=-\frac{5}{28}

Therefore,

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}

4 0
3 years ago
Why do you think items that come in a larger quantity cost less per unit
MAXImum [283]
They cost less because there are more items in stock meaning that there isn't a limit here is another way of thinking if there are less Items then they can charge you more per item because they know you are gonna want it but if there are tons of that one item they there kinda like eh then you think oh I can live without that....... Hope this helps

7 0
2 years ago
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